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mario62 [17]
3 years ago
9

You need 8 oz of red paint and 12 oz of blue paint to make purple paint. How much red paint is needed for 15 oz of blue paint?

Mathematics
1 answer:
olga2289 [7]3 years ago
4 0

Answer:

10oz

Step-by-step explanation:

Solve

<h2>\frac{8}{12} = \frac{x}{15}</h2><h2>x=10</h2><h2></h2>
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Can you help answer these:
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1) -3 x 3=-9

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3)20x5=100

4) 21x-3=-63

5) -2x3x-4=24

note: negative x positive= negative

negative x negative=positive

positive x positive= positive

Step-by-step explanation:

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6 0
3 years ago
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Calculate the average rate of change for the given graph from x = -2 to x = 0
Ludmilka [50]

Answer: x goes from 0 to 2, y changes from 0 to -2

Step-by-step explanation:

7 0
3 years ago
$20,000 is borrowed at an interest rate of 15% p.a. (per annum) to be paid back over 10
leonid [27]

Answer:

30000 simple interest ,50000 total repayment.

Step-by-step explanation:

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3 0
3 years ago
How to write (-2,-1) and (2,7) in y=mx+b form
nasty-shy [4]

y = 2x + 3

the equation of a line in slope-intercept form is

y = mx + b ( m is the slope and b the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁) = (- 2, - 1) and (x₂, y₂) = (2, 7)

m = \frac{7+1}{2+2} = \frac{8}{4} = 2

y = 2x + b ← is the partial equation

to find b substitute either of the 2 points into the partial equation

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5 0
4 years ago
Kesha threw her baton up in the air from the marching band platform during practice. The equation h(t) = −16t² + 54t + 40 gives
lapo4ka [179]

Answer:

a) 40 feet

b) 54 ft/min

c) 4 mins

Step-by-step explanation:

Solution:-

- Kesha models the height ( h ) of the baton from the ground level but thrown from a platform of height hi.

- The function h ( t ) is modeled to follow a quadratic - parabolic path mathematically expressed as:

                           h ( t ) = −16t² + 54t + 40

Which gives the height of the baton from ground at time t mins.

- The initial point is of the height of the platform which is at a height of ( hi ) from the ground level.

- So the initial condition is expressed by time = 0 mins, the height of the baton h ( t ) would be:

                         h ( 0 ) = hi = -16*(0)^2 + 54*0 + 40

                         h ( 0 ) = hi = 0 + 0 + 40 = 40 feet

Answer: The height of the platform hi is 40 feet.

- The speed ( v ) during the parabolic path of the baton also varies with time t.

- The function of speed ( v ) with respect to time ( t ) can be determined by taking the derivative of displacement of baton from ground with respect to time t mins.

                        v ( t ) = dh / dt

                        v ( t )= d ( −16t² + 54t + 40 ) / dt

                        v ( t )= -2*(16)*t + 54

                        v ( t )= -32t + 54

- The velocity with which Kesha threw the baton is represented by tim t = 0 mins.

Hence,

                        v ( 0 ) = vi = -32*( 0 ) + 54

                        v ( 0 ) = vi = 54 ft / min

Answer: Kesha threw te baton with an initial speed of vo = 54 ft/min

- The baton reaches is maximum height h_max and comes down when all the kinetic energy is converted to potential energy. The baton starts to come down and cross the platform height hi = 40 feet and hits the ground.

- The height of the ball at ground is zero. Hence,

                     h ( t ) = 0

                     0 = −16t² + 54t + 40

                     0 = -8t^2 + 27t + 20

- Use the quadratic formula to solve the quadratic equation:

                     

                    t = \frac{27+/-\sqrt{27^2 - 4*8*(-20)} }{2*8}\\\\t = \frac{27+/-\sqrt{1369} }{16}\\\\t = \frac{27+/-37 }{16}\\\\t =  \frac{27 + 37}{16} \\\\t = 4

Answer: The time taken for the baton to hit the ground is t = 4 mins

3 0
3 years ago
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