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Sliva [168]
3 years ago
13

Without tax, a cell phone had a price of 200. including tax, it was 230. At what rate was the phone taxed?

Mathematics
1 answer:
Tcecarenko [31]3 years ago
6 0

Answer:

15% tax

Step-by-step explanation:

$230.00 - $200.00=$30.00 / $200.00=.15 or 15%

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. Look at each equation and possible solution. Is the solution correct? Select Yes or No for
insens350 [35]
A. No B. No C. Yes I honestly don’t know if that’s 100% right tho
4 0
3 years ago
The explicit formula for an arithmetic sequence is an = 20 + (n − 1)(2). What is the 200th term?
Andrews [41]

Answer:

a_{200}=418

Step-by-step explanation:

The explicit formula for an arithmetic sequence is given by :

a_n=20+(n-1)2 ...(1)

We need to find the 200th term of the sequence.

Put n = 200 in equation (1)

a_{200}=20+(200-1)2\\\\=20+199\times 2\\\\=418

So, the 200th term of the sequence is 418.

7 0
3 years ago
3. Maxine has assets worth $145,000 and liabilities totaling $75,000. What is Maxine's net worth?
BabaBlast [244]
Answer: C.) $70,000

Explanation:
Assets - Liabilities = Net worth
$145,000 - $75,000 = $70,000
5 0
3 years ago
Read 2 more answers
What is the equation of the line through (1, 6) and (0, 2)?
ASHA 777 [7]

Answer:

y = 4x + 2

Step-by-step explanation:

y = mx + b

m is the slope

b is the y-intercept

6 0
3 years ago
The weight of baby goats is believed to be Normally distributed, with a mean of 5.75 pounds. The average weight of a random samp
Julli [10]

Answer:

The standard error of the mean is 0.0783.

Step-by-step explanation:

The Central Limit Theorem helps us find the standard error of the mean:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

The standard deviation of the sample is the same as the standard error of the mean. So

SE_{M} = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\sigma = 0.35, n = 20

So

SE_{M} = \frac{\sigma}{\sqrt{n}}

SE_{M} = \frac{0.35}{\sqrt{20}}

SE_{M} = 0.0783

The standard error of the mean is 0.0783.

7 0
3 years ago
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