Answer:
There are 1% probability that the last person gets to sit in their assigned seat
Step-by-step explanation:
The probability that the last person gets to sit in their assigned seat, is the same that the probability that not one sit in this seat.
If we use the Combinatorics theory, we know that are 100! possibilities to order the first 99 passenger in the 100 seats.
LIke we one the probability that not one sit in one of the seats, we need the fraction from the total number of possible combinations, of combination that exclude the assigned seat of the last passenger. In other words the amount of combination of 99 passengers in 99 seats: 99!
Now this number of combination of the 99 passenger in the 99 sets, divide for the total number of combination in the 100 setas, is the probability that not one sit in the assigned seat of the last passenger.
P = 99!/100! = 99!/ (100 * 99!) = 1/100
There are 1% probability that the last person gets to sit in their assigned seat
Answer:
3.92$
Step-by-step explanation:
Answer:
OPTION D
Step-by-step explanation:
We have to determine which option determines the function given above.
To determine the function, just substitute the values and compare LHS and RHS.
we have 
Here, 
is the domain and 
is the co-doamin.
Therefore, 
Now, OPTION A: 
Substitute x = 4. We get f(x) = 3 
18.
So, OPTION A is rejected.
Similarly, OPTION B: 
Substitute x = 4. We get f(4) = 22 18.
It is rejected as well.
Now, for OPTION C: 
Substitute x = 4. We get f(4) = -3 18.
So, OPTION C is also rejected.
OPTION D: 
Substitute x = 4. We get f(4) = 18.
Substitute the remaining points in domain as well. We notice that it exactly matches the given function. So, OPTION D is the answer.
Answer:the answer is A) g(x) is shifted down 2 units
Step-by-step explanation:
Since the last number after the parentheses represents the vertical shift, taking away the +2, leaves you with 0 meaning that there is no vertical shift, so the function lies on the x-axis. The graph shifts down 2 units
