The grocery store clerk

Will mark brainliest. Please help ASAP

pantera1 [17]

Answer:

1/4000

1 milimeter on paper means 4000 in real

5 0

2 years ago

Y=2x-6 slope? y- intercept?

krek1111 [17]

Answer:

The slope is 2/1 and the y-intercept is -6.

Step-by-step explanation:

With the y=mx+b formula, m is the slope and b is the intercept.

4 0

3 years ago

Read 2 more answers

According to a study conducted in one city, 35% of adults in the city have credit card debts more than $2.000. A simple random s

BabaBlast [244]

Answer:

Binomial; \mu p=87.5, \sigma p=7.542

Step-by-step explanation:

a distribution is said be a binomial distribution iff

The probability of success of that event( let it be p) is same for every trial
each trial should have 2 outcome : p or (1-p) i.e, success or failure only.
there are fixed number of trials (n)
the trials are independent

here, the trials are obviously independent ( because, one person's debt doesn't influence the other person's)

here n=250

the probability of success(0.35) is same for every trial

(35/100=0.35 is the required p here)

$\mu_{p} =n*p=250*\frac{35}{100} =250*0.35=87.5$

[since, the formula for $\mu _{p} =n*p$ ]

$\sigma _{p} =\sqrt{n*(p)*(1-p)} = \sqrt{250*0.35*(1-0.35)} = 7.542 ( approximately)$

[since, the formula for [tex]\sigma _{p} =\sqrt{n*(p)*(1-p)}

therefore, it is Binomial; \mu p=87.5, \sigma p=7.542

4 0

3 years ago

Two competitive neighbours build rectangular pools that cover the same area but are different shapes. Pool A has a width of (x +

GenaCL600 [577]

Answer:

a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

b) Area of pool A is equal to area of pool B equal to 24.44 meters.

Solution:

Let’s first calculate area of pool A .

Given that width of the pool A = (x+3)

Length of the pool A is 3 meter longer than its width.

So length of pool A = (x+3) + 3 =(x + 6)

Area of rectangle = length x width

So area of pool A =(x+6) (x+3) ------(1)

Let’s calculate area of pool B

Given that length of pool B is double of width of pool A.

So length of pool B = 2(x+3) =(2x + 6) m

Width of pool B is 4 meter shorter than its length,

So width of pool B = (2x +6 ) – 4 = 2x + 2

Area of rectangle = length x width

So area of pool B =(2x+6)(2x+2) ------(2)

Since area of pool A is equal to area of pool B, so from equation (1) and (2)

(x+6) (x+3) =(2x+6) (2x+2)

On solving above equation for x

(x+6) (x+3) =2(x+3) (2x+2)

x+6 = 4x + 4

x-4x = 4 – 6

x = $\frac{2}{3}$

Dimension of pool A

Length = x+6 = ( $\frac{2}{3}$ ) +6 = 6.667m

Width = x +3 = ( $\frac{2}{3}$ ) +3 = 3.667m

Dimension of pool B

Length = 2x +6 = 2( $\frac{2}{3}$ ) + 6 = $\frac{22}{3}$ = 7.333m

Width = 2x + 2 = 2( $\frac{2}{3}$ ) + 2 = $\frac{10}{3}$ = 3.333m

Verifying the area:

Area of pool A = ( $\frac{20}{3}$ ) x ( $\frac{11}{3}$ ) = $\frac{220}{9}$ = 24.44 meter

Area of pool B = ( $\frac{22}{3}$ ) x ( $\frac{10}{3}$ ) = $\frac{220}{9}$ = 24.44 meter

Summarizing the results:

(a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

(b)Area of pool A is equal to Area of pool B equal to 24.44 meters.

5 0

3 years ago

PLEASE HELP IVE ASKED THIS QUESTION 3 TIMES PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!

worty [1.4K]

THEOREM:

h² = p² + b² where h is hypotenuse, b is base and p is perpendicular.

ANSWER:

[3] By pythagorean theorem,

x² = 14² + 9²
x² = 196 + 81
x² = 277
x = √277
x = 16.64 rounded.

[4] By pythagorean theorem,

x² = 32² + 24²
x² = 1024 + 576
x² = 1600
x = √1600
x = 40.

[5] By pythagorean theorem,

(2x)² = 21² – 12.6²
4x² = 441 – 158.76
4x² = 284.24
x² = 284.24/4 = 70.56
x = √70.56
x = 8.4

[6] By tangent property,

7x – 29 = 2x + 16
7x – 2x = 16 + 29
5x = 45
x = 9.

So, WX = 7(9) – 29 = 63 – 29

WX = 34

4 0

3 years ago

The grocery store clerk​

The grocery store clerk