Answer:
2.29 ft of side length and 1.14 height
Step-by-step explanation:
a) Volume V = x2h, where x is side of square base and h is hite.
Then surface area S = x2 + 4xh because box is open.
b) From V = x2h = 6 we have h = 6/x2.
Substitude in formula for surface area: S = x2 + 4x·6/x2, S = x2 + 24/x.
We get S as function of one variable x. To get minimum we have to find derivative S' = 2x - 24/x2 = 0, from here 2x3 - 24 = 0, x3 = 12, x = (12)1/3 ≅ 2.29 ft.
Then h = 6/(12)2/3 = (12)1/3/2 ≅ 1.14 ft.
To prove that we have minimum let get second derivative: S'' = 2 + 48/x3, S''(121/3) = 2 + 48/12 = 6 > 0.
And because by second derivative test we have minimum: Smin = (12)2/3 + 4(12)1/3(12)1/3/2 = 3(12)2/3 ≅ 15.72 ft2
Answer:
It would be a profit of .35 cents
Step-by-step explanation:
Answer:
10
Step-by-step explanation:
5! divided by all the repeats so 3!2! = 10 ways
Answer:
Step-by-step explanation:
Given that:
sin2xcos x + cos2xsin x = -1
Recall that;
SInAcosB + cosASinB = SIn (A+B)
SIn (2x +x) = -1
Sin (3x) = -1
![x = \bigg [\dfrac{Sin ^{-1} (-1)}{3} \bigg ]](https://tex.z-dn.net/?f=x%20%3D%20%5Cbigg%20%5B%5Cdfrac%7BSin%20%5E%7B-1%7D%20%28-1%29%7D%7B3%7D%20%20%5Cbigg%20%5D)
The answer is: 1.25x + 1.75
