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VashaNatasha [74]
3 years ago
7

Help Find x. Round to the nearest tenth. I 64 8

Mathematics
1 answer:
inessss [21]3 years ago
7 0

Answer:

x= 3.5 (nearest tenth)

Step-by-step explanation:

Please see the attached picture for the full solution.

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You can walk 1/2 miles in half an hour what is your average speed
NeTakaya

Answer:  The average speed is 3 mph.

Step-by-step explanation:

You would divide the distance by the amount of time it would take to get there. So in this case,

1.5/0.5=3

4 0
3 years ago
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PLEASEEE HELP ASAP! *grade 9 work* and show your work!!
lidiya [134]

Answer:

at 0  the amount is 5

1 is 7.5

2 is 10

3 is 12.5

the initial value is the y intercept when the value ox x=0

the initial value is 5

the rate of change is the total change of a function of the out put (y) divided by the change of the input (x)

f(x2)-f(x1)/x2-x1

10-7.5/2-1

2.5/1=2.5

or m=y2-y1/x2/x1=10-7.5/2-1=2.5

y=2.5x+5

5 0
3 years ago
Please helpppppp!!!!​
LiRa [457]

Answer:

The first answer choice.

Step-by-step explanation:

The scatterplot has both points (2,2) and (3,2) and the other options do not include the choices.

5 0
4 years ago
Suppose the force acting on a column that helps to support a building is a normally distributed random variable X with mean valu
Sauron [17]

Answer:

(1) 0.4207

(2) 0.7799

Step-by-step explanation:

Given,

Mean value,

\mu = 15.0

Standard deviation,

\sigma = 1.25

(1) P(X ≥ 17.5) = 1 - P( X ≤ 17.5)

= 1- P(\frac{x-\mu}{\sigma} \leq \frac{17.5-\mu}{\sigma})

=1-P(z\leq \frac{17.5 - 15}{1.25})

=1-P(z\leq \frac{2.5}{1.25})

=1-P(z\leq 2)

=1- 0.5793   ( By using z-score table )

= 0.4207

(2) P(14 ≤ X ≤ 18) = P(X ≤ 18) - P(X ≤ 14)

=P(z\leq \frac{18 - 15}{1.25}) - P(z\leq \frac{14 - 15}{1.25})

=P(z\leq \frac{3}{1.25}) - P(z\leq -\frac{1}{1.25})

=P(z\leq 2.4) - P(z\leq -0.8)

= 0.9918 - 0.2119

= 0.7799

8 0
3 years ago
Which expression is equivalent to -5(2x – 10)?<br> Help ples
ArbitrLikvidat [17]
The answer is c.

-5(2x-10)=
Distribute
-10x+50

-10(x-5)= -10x+50
5 0
3 years ago
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