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VashaNatasha [74]
2 years ago
7

Help Find x. Round to the nearest tenth. I 64 8

Mathematics
1 answer:
inessss [21]2 years ago
7 0

Answer:

x= 3.5 (nearest tenth)

Step-by-step explanation:

Please see the attached picture for the full solution.

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6a*2-a-15 factoring and soulutions
eduard
6a(2)-a-15
=12a+-a+-15
Combine Like Terms:<span>=<span><span><span>12a</span>+<span>−a</span></span>+<span>−15</span></span></span><span>=<span><span>(<span><span>12a</span>+<span>−a</span></span>)</span>+<span>(<span>−15</span>)</span></span></span><span>=<span><span>11a</span>+<span>−15</span></span></span>Answer:<span>=<span><span>11a</span>−15</span></span> <span>

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4 0
3 years ago
Mindy left at 8 a.M. And will arrive at 1 p.M.; jelly left at 8 a.M. And will arrive at 2 p.M. How many miles is the trip if Kel
uysha [10]

Answer:

300 miles

Step-by-step explanation:

The distance equation is D = RT

Where

D is the distance

R is the rate

T is the time

<u>Mindy</u>

8 am to 1 pm = 5 hours

<u>Kelly</u>

8 am to 2 pm = 6 hours

Kelly's rate is 10 mph SLOWER than mindy, so if we let Mindy's rate be "m", so Kelly's rate will be " m - 10 "

Now using the distance equation, we can write:

Mindy >>> D = RT >>> D = 5m

Kelly >>> D = RT >>>  D = 6(m-10) >>> D = 6m - 60

Since both the distances are equal, we can write:

5m = 6m - 60

m = 60

We want the distance, we know:

D = 5m

D = 5(60)

D = 300 miles

The distance is 300 miles

5 0
3 years ago
Y varies inversely with x <br><br> k = 0.6<br><br> What is the value of x when y is 0.6?
skad [1K]

to find X when K is known

 divide K by  Y

0.6/0.6 = 1

X = 1

7 0
3 years ago
Solve the inequality.<br> -1.5(4x+1) ≥ 45-25(x+1)
777dan777 [17]

Answer:

x ≥ 21.5/19

Step-by-step explanation:

-1.5(4x + 1) ≥ 45 - 25(x + 1)

-6x - 1.5 ≥ 45 - 25x - 25

-6x + 25x ≥ 45 - 25 + 1.5

19x ≥ 21.5

x ≥ 21.5/19

3 0
2 years ago
Sarah and Riley are going to make 2 batches of muffins. The smaller batch is 23the size of the larger batch. The recipe for the
CaHeK987 [17]
21...is equal to 11+10
5 0
3 years ago
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