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Arada [10]
3 years ago
8

6. A home repair crew charges seventy-five dollars per day plus two

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
6 0

Answer:

6 hours

Step-by-step explanation:

all you do is 10 divided by 6 then 0 -3-3-6-6-5-6 and you gt 10

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Solve the proportion t+4 / t-2 = 1/4
Lera25 [3.4K]

t+4 / t-2 = 1/4

t=-6 for your answer!

8 0
3 years ago
Give A ={a,b,c} and B = {c, a}, which of the following is not true
Alborosie

Answer:

The second one

Step-by-step explanation:

B c A

Because B has c and a, which is part of A (A={a, b, c})

8 0
3 years ago
The manager of the Danvers-Hilton Resort Hotel stated that the mean guest bill for a weekendis $600 or less. Amember of the hote
alexdok [17]

Answer:

H_{0}: \mu \leq 600\text{ dollars}\\H_A: \mu > 600\text{ dollars}

Step-by-step explanation:

We are given the following in the question:

Manager's claim: The mean guest bill for a weekend is $600 or less.

A member of the hotel’s accounting staff noticed that the total charges for guest bills have been increasing in recent months.

A sample of weekend guest bills were collected to test the manager’s claim.

We design the null and alternate hypothesis in the following manner:

H_{0}: \mu \leq 600\text{ dollars}\\H_A: \mu > 600\text{ dollars}

Conclusion when null hypothesis cannot be rejected:

When we fail to reject the null hypothesis and accept the null hypothesis, thus, we have enough evidence to support the manager's claim that the mean guest bill for a weekend is $600 or less.

Conclusion when null hypothesis can be rejected:

When the null hypothesis is rejected, we accept the alternate hypothesis.

Thus, there are not sufficient evidence to support the manager's claim  that the mean guest bill for a weekend is $600 or less.

5 0
3 years ago
The function f(x)=(x-5)^2 +2 is not one-to-one. Identify a restricted domain that makes the function one-to-one, and find the in
Anon25 [30]

We have been given a quadratic function f(x)=(x-5)^{2} +2 and we need to restrict the domain such that it becomes a one to one function.

We know that vertex of this quadratic function occurs at (5,2).

Further, we know that range of this function is [2,\infty).

If we restrict the domain of this function to either (-\infty,5] or [5,\infty), it will become one to one function.

Let us know find its inverse.

y=(x-5)^{2}+2

Upon interchanging x and y, we get:

x=(y-5)^{2}+2

Let us now solve this function for y.

(y-5)^{2}=x-2\\
y-5=\pm \sqrt{x-2}\\
y=5\pm \sqrt{x-2}\\

Hence, the inverse function would be f^{-1}(x)=5+\sqrt{x-2} if we restrict the domain of original function to [5,\infty) and the inverse function would be f^{-1}(x)=5-\sqrt{x-2} if we restrict the domain to (-\infty,5].

8 0
3 years ago
Five is three more than a number n. <br> I don't understand this at all!
olga2289 [7]

So what they are telling you is that 5 is three higher than the variable n.
So n = 5-3 
so n is 2. 
4 0
3 years ago
Read 2 more answers
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