Answer: (1) x²y (2) 7pqr (3) a (4) 6a² (5) y³z²
Step-by-step explanation:
(1) x^4y³ and x²y
x^4y³ = x²y(x²y²)
x²y = x²y
Therefore the Highest Common factor
x²y which is the common factor.
(2) 14p²qr^4 = 2 x 7 x p² x q x r^4
49p²q²r = 7 x 7 x p² x q² x r
35pqr = 5 x 7 x p x q x r
Therefore HCF = 7 x p x q x r
= 7pqr
(3) -a^5 = -( a x a x a x a x a )
= -(a^5)
ab³ = a x b x b x b
Therefore HCF = a
(4) 6a² = 2 x 3 x a x a
-18a6 = -( 2 x3 x 3 x a x a x a x a x a x a)
-12a² = -( 2 x 2 x 3 x a x a )
Therefore HCF = 2 x 3 x a²
= 6a²
(5) 3y³z² = 3 x y x y x y x z x z , 3 x y³ x z²
15y^4z² = 3 x 5 x y x y x y x y x y x z x z, 3 x 5 x y^4 x z²
y^6z³ = y^6 x z³
Therfore HCF = y³ x z²
= y³z²
Answer:
5 times the sun of 2x and 3y equals the difference of y to the second power and 2x cubed
Arc SCD is two times of angle SED, so arc SCD is 8x+22. Now set 8x+22, 5x-8, and 11x+10 to 360 and solve for x
4. The point Z is the orthocenter of the triangle.
5. The length of GZ is of 9 units.
6. The length of OT is of 9.6 units.
<h3>What is the orthocenter of a triangle?</h3>
The orthocenter of a triangle is the point of intersection of the three altitude lines of the triangle.
Hence, from the triangle given in the end of the answer, point Z is the orthocenter of the triangle.
For the midpoints connected through the orthocenter, the orthocenter is the midpoint of these segments, hence:
- The length of segment GZ is obtained as follows: GZ = 0.5 GU = 9 units. -> As z is the midpoint of the segment.
- The length of segment OT is obtained as follows: OT = 2ZT = 2 x 4.8 = 9.6 units.
<h3>Missing Information</h3>
The complete problem is given by the image at the end of the answer.
More can be learned about the orthocenter of a triangle at brainly.com/question/1597286
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