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Romashka [77]
2 years ago
15

Rewrite the product as a power:

(-a)^{3} b^{3}" alt="(-a)^{3} b^{3}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
anastassius [24]2 years ago
4 0

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{ - a}^{3} . {b}^{3}  = ( { - a \times b})^{3}  = ( { - ab})^{3}  \\

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Factor wheels show all the
Zielflug [23.3K]

answer: 2 × 2 × 2 × 2 × 2 = 32

Step-by-step explanation:

32 \\  = 16 \times 2  \\ = 4 \times 4 \times 2  \\ = 2 \times 2 \times 2 \times 2 \times 2

3 0
2 years ago
Help please pick an answer from the ones provided
wolverine [178]

Answer:

c is the correct answer..........

4 0
2 years ago
Read 2 more answers
Find the intersection point between the lines of equations:<br><br>2x-y+6=0 and 2x+3y-6=0 ​
Ugo [173]

Step-by-step explanation:

The two equation will intersect each other at the point which will be the solution of the given two equations , and the given equations are ,

\implies 2x -y +6=0\\\\\implies 2x + 3y -6=0

On subtracting the given equations we have,

\implies -y - 3y +6 -(-6) = 0 \\\\\implies -4y = -12 \\\\\implies y = -12/-4\\\\\implies y = 3

Put this value in any equation , we have ,

\implies 2x -3 +6 =0\\\\\implies 2x = -3 \\\\\implies x =\dfrac{-3}{2} \\\\\implies x =-1.5

Hence the lines will Intersect at ,

\implies\underline{\underline{ Point=(-1.5, 3)}}

8 0
2 years ago
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Please help this is due at 11
ollegr [7]

me at 1:36pm: oh no,  i hope he got his answer

8 0
3 years ago
90,88,88,87,84,95,90,80,98,and 100
Nitella [24]
In order to find the median the 1st thing I would do is put the number in order
80,84,87,88,88,90,90,95,98,100 
then cross them out Start with left then go the right and so on...
until you get 1 number in the middle left (Since theirs 2 numbers in the middle add them up and divide by two ) 88+90=178   178/2=89
Median = 89 

Now in Order to find the mean add up all the numbers and divide by however many numbers their are 
You should get 900 then divide by 10 because their were 10 numbers 

So Median=89 &  Mean=90 
7 0
3 years ago
Read 2 more answers
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