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Andrews [41]
3 years ago
13

Multiple choice please answer please

Mathematics
1 answer:
joja [24]3 years ago
6 0

Answer:

A

Step-by-step explanation:

Using the cosine ratio in the right triangle

cosA = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{2}{3} , thus

A = cos^{-1} (\frac{2}{3} ) ≈ 48° → A

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Divide both sides by 7
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What is the following quotient? 5/√11-√3
kati45 [8]

ANSWER

\frac{5( \sqrt{11}  +  \sqrt{3} )} {8}

EXPLANATION

The given rational function is

\frac{5}{ \sqrt{11} -  \sqrt{3}}

We need to rationalize the denominator by multiplying both the numerator and the denominator by the conjugate of

\sqrt{11}  -  \sqrt{3}

which is

\sqrt{11}   +  \sqrt{3}

When we rationalize we obtain:

\frac{5( \sqrt{11}  +  \sqrt{3} )}{(\sqrt{11}  - \sqrt{3} )( \sqrt{11}  +  \sqrt{3} )}

The denominator is now a difference of two squares:

(a - b)(a + b) =  {a}^{2}  -  {b}^{2}

We apply this property to get

\frac{5( \sqrt{11}  +  \sqrt{3} )}{( \sqrt{11}) ^{2}    -  ( \sqrt{3}) ^{2}  )}

\frac{5( \sqrt{11}  +  \sqrt{3} )}{11   -  3}

This simplifies to

\frac{5( \sqrt{11}  +  \sqrt{3} )} {8}

Or

\frac{5 }  {8}\sqrt{11}  + \frac{5 }  {8}\sqrt{3}

8 0
3 years ago
Read 2 more answers
A bag contains 9 red marbles, 18 orange marbles, 2 yellow marbles, and 5 purple marbles. A marble is drawn at random from the ba
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Answer:

8/17

Step-by-step explanation:

total balls= 9 + 18 + 2 + 5 = 34

balls drawn should NOT be Orange.

so, 34 - 18 (as there are 18 orange balls)

16 balls

probability= 16/34 = 8/17

answer = 8/17

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Which of the following would be a good argument to lease rather than buy?
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The sugar content of the syrup in canned peaches is normally distributed. A random sample of n = 10 cans yields a sample standar
Serggg [28]

Answer:

The 95% confidence interval is given by:

3.30<σ<8.76

Step-by-step explanation:

1) Data given and notation

s=4.798 represent the sample standard deviation

\bar x represent the sample mean

n=10 the sample size

Confidence=95% or 0.95

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=10-1=9

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.025,9)" "=CHISQ.INV(0.975,9)". so for this case the critical values are:

\chi^2_{\alpha/2}=19.022

\chi^2_{1- \alpha/2}=2.700

And replacing into the formula for the interval we got:

\frac{(9)(4.798)^2}{19.022} \leq \sigma \frac{(9)(4.798)^2}{2.700}

10.892 \leq \sigma^2 \leq 76.736

Now we just take square root on both sides of the interval and we got:

3.30 \leq \sigma \leq 8.76

So the best option would be:

3.30<σ<8.76

7 0
3 years ago
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