Find the perimeter of the square in the coordinate plane below. Round your answer to two decimal places.
2 answers:
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Sure. I'm not sure if I like the computer aided instruction.
so in the first block they want sin A and in the second block sin A cos A
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Proof,
Looks like the box is cos θ
Given:
A square base pyramid whose base length is 10 in. and height of triangular surface is 4 in.
To find:
The surface area of the pyramid to the nearest whole number.
Solution:
A square base pyramid contains square base with edge 10 in. and 4 congruent triangles with base 10 in. and height 4 in.
Area of a square is
So, area of square base is 100 sq. in.
Area of a triangle is
So, area of each triangular surface is 20 sq. in.
Now, the total surface area of the pyramid is
Total area = Area of square base + Area of 4 congruent triangles.
Therefore, the area of the pyramid is 180 sq. in.