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Vsevolod [243]
4 years ago
14

You but 125 tickets to an amusement park that each cost $19.50. What is the total cost of the 125 tickets

Mathematics
2 answers:
vodka [1.7K]4 years ago
8 0

1 ticket = 19.50

25 tickets = 19.50 * 25 = 2437,5 $

mixer [17]4 years ago
4 0

1 ticket costs $19.50

You are buying 125 tickets

Multiply 125 with 19.50

125 x 19.50 = 2437.50

$2437.50 is the total cost of all the tickets

hope this helps

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How many different ways can the letters of “football” be arranged
makvit [3.9K]
<h3>Answer:   10,080</h3>

Explanation:

There are 8 letters so there are 8! = 8*7*6*5*4*3*2*1 = 40,320 permutations of those letters. However, the letters "O" and "L" show up twice each, so we must divide by 2! = 2*1 = 2 for each instance this happens.

So,

(8!)/(2!*2!) = (40,320)/(2*2) = (40,320)/4 = 10,080

is the number of ways to arrange the letters of "football".

The reason we divide by 2 for each instance of a duplicate letter is because we can't tell the difference between the two "O"s or the two "L"s. If there was a way to distinguish between them, then we wouldnt have to divide by 2.

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F(x) = x^2 + 7x-4 find the second derivative
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We know that f(x) = 7x + 8. So, take the derivative of this function with respect to x.

This gives

f'(x) = 7

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Darien's kitten weighs 2.25 pounds. Her dog weighs 10 times the weight of the kitten. How much does her dog weigh?
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Answer: 22.5 LBS (Or Pounds)

Work: After I multiplied 2.25 by 10, I received the answer above. Happy Holidays! :)

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3 years ago
Research is being conducted to determine if a large supermarket is discriminating against African Americans. For the supermarket
Helga [31]

Answer:

A. Ha: p < 0.3

Using the significance level for example \alpha=0.05 we see that p_v>\alpha so we have enough evidence at this significance level to FAIL to reject the null hypothesis. And on this case we can say that the proportion of employees that received the merit raise are African American  is not significantly less than 0.3 or 30%.

Step-by-step explanation:

1) Data given and notation

n=60 represent the random sample taken  

X=17 represent the employees that received the merit raise are African American

\hat p=\frac{17}{60}=0.283 estimated proportion of employees that received the merit raise are African American

p_o=0.3 is the value that we want to test  

\alpha represent the significance level (no given)  

z would represent the statistic (variable of interest)  

p_v represent the p value (variable of interest)  

p= population proportion of employees that received the merit raise are African American

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion of employees that received the merit raise are African American is less than 0.3 or 30%. :  

Null Hypothesis: p \geq 0.3

Alternative Hypothesis: p

A. Ha: p < 0.3

We assume that the proportion follows a normal distribution.  

This is a one tail lower test for the proportion of employees that received the merit raise are African American .

The One-Sample Proportion Test is "used to assess whether a population proportion \hat p is significantly (different,higher or less) from a hypothesized value p_o".

<em>Check for the assumptions that he sample must satisfy in order to apply the test </em>

a)The random sample needs to be representative: On this case the problem no mention about it but we can assume it.

b) The sample needs to be large enough

np_o =60*0.3=18>10

n(1-p_o)=60*(1-0.3)=42>10

3) Calculate the statistic  

The statistic is calculated with the following formula:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o(1-p_o)}{n}}}

On this case the value of p_o=0.3 is the value that we are testing and n = 60.

z=\frac{0.283 -0.3}{\sqrt{\frac{0.3(1-0.3)}{60}}}=-0.287

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

Based on the alternative hypothesis the p value would be given by:

p_v =P(Z  

Using the significance level for example \alpha=0.05 we see that p_v>\alpha so we have enough evidence at this significance level to FAIL to reject the null hypothesis. And on this case we can say that the proportion of employees that received the merit raise are African American  is not significantly less than 0.3 or 30%.

3 0
4 years ago
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