1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Wittaler [7]
3 years ago
15

25 points pls help this is really hard

Mathematics
2 answers:
Katarina [22]3 years ago
8 0

Answer:

10

Step-by-step explanation:

you do step by step math and after you do that you will get 10

Mariana [72]3 years ago
3 0

Answer:

10

Step-by-step explanation:

You might be interested in
Marco is 8 years younger than his brother Paolo. If their product of their ages is 105, how old is Marco? plz help
Nina [5.8K]

Answer:

Marco's age is 7 years old

Step-by-step explanation:

Let

x ----> Marco's age

y ----> Paolo's age

we know that

x=y-8 ----> y=x+8 ----> equation A

xy=105 ----> equation B

substitute equation A in equation B

x(x+8)=105

x^2+8x-105=0

Solve the quadratic equation

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^2+8x-105=0

so

a=1\\b=8\\c=-105

substitute in the formula

x=\frac{-8(+/-)\sqrt{8^{2}-4(1)(-105)}} {2(1)}

x=\frac{-8(+/-)\sqrt{484}} {2}

x=\frac{-8(+/-)22} {2}

x=\frac{-8(+)22} {2}=7

x=\frac{-8(-)22} {2}=-15

Remember that the solution cannot be a negative number

so

The solution is x=7

therefore

Marco's age is 7 years old

4 0
3 years ago
R leaks out of a barrel so that the rate of change in the water level is proportional to the square root of the depth of the wat
Irina-Kira [14]
Let y(t) represent the level of water in inches at time t in hours. Then we are given ...
  y'(t) = k√(y(t)) . . . . for some proportionality constant k
  y(0) = 30
  y(1) = 29

We observe that a function of the form
  y(t) = a(t - b)²
will have a derivative that is proportional to y:
  y'(t) = 2a(t -b)

We can find the constants "a" and "b" from the given boundary conditions.
At t=0
  30 = a(0 -b)²
  a = 30/b²
At t=1
  29 = a(1 - b)² . . . . . . . . . substitute for t
  29 = 30(1 - b)²/b² . . . . . substitute for a
  29/30 = (1/b -1)² . . . . . . divide by 30
  1 -√(29/30) = 1/b . . . . . . square root, then add 1 (positive root yields extraneous solution)
  b = 30 +√870 . . . . . . . . simplify

The value of b is the time it takes for the height of water in the tank to become 0. It is 30+√870 hours ≈ 59 hours 29 minutes 45 seconds
5 0
3 years ago
If it if 2 multiplies by x and the answer if 8 . What is the value of x ??
Morgarella [4.7K]
2x=8
(Divide 2 from both sides)
x=4

8 0
3 years ago
Help please!!!!!!!!
sp2606 [1]

Answer:

A

Step-by-step explanation:

g(x)=\frac{x-7}{4}

g(15)=2

8 0
3 years ago
Read 2 more answers
Please help asap I’ll give you 20 points
natima [27]

Answer:

first one is left second one is right

3 0
2 years ago
Read 2 more answers
Other questions:
  • It took Jaytree 42 seconds to rip about half a DVD. About what is Jaytree’s “ripping rate” in DVDs per minute?
    14·1 answer
  • Can a right triangle be formed using these squares
    13·2 answers
  • 5x+8=23 <br>im so lost on how to solve these equations
    10·1 answer
  • What is an equation of the line that passes through the point
    15·1 answer
  • If p varies directly with T and p =105 when T=400.Find p when T =500
    14·1 answer
  • Try the numbers 22, 23, 24, 25 in the equation 4/3 = 32/d
    9·1 answer
  • Without graphing determine whether the system of linear equations has one solution infinitely many solutions or no solution expl
    13·2 answers
  • How can you use a bar diagram to check the accuracy of the solution to a ratio or rate problem
    8·1 answer
  • The CEO of a company wants to determine whether taking the employees to a company retreat would boost their morale. He decides t
    13·2 answers
  • Please help! and thank you so much!
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!