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Irina18 [472]
2 years ago
11

A restaurant serves you a 16- fluid ounces glass of juice that is 30% ice. How many fluid ounces of juice do you actually get

Mathematics
1 answer:
Bas_tet [7]2 years ago
6 0
30 percent of 16 is 4.8 so you actually get 4.8 fluid ounces of juice
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ANY MATH EXPERTS PLS HELP RN I GOT 30 MIN LEFT I PUT 100 POINTS
Alexeev081 [22]

-8/5

Remember "rise over run." Rise means the vertical distance and run id the horizontal between the two points.

3 0
2 years ago
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The temperature at 7pm was 45 degrees Fahrenheit. From 7pm to 11pm the temperature decreased 5 degrees each hour. Which equation
Svetllana [295]

t = 45 - 5(11-7)

Hope that helps:)

7 0
3 years ago
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3 lines are shown. A line with points C, A, F intersects a line with points E, A, B at point A. A line extends from point A to p
Verizon [17]

Answer:

m < EAD = 29 degrees

m < CAB = 119 degrees

Given :

The question states that m < CAE = m<FAB = 61 degrees and m<DAF = 90 degrees

Solution:

1. Since line CAF and EAB intersect each other, m<CAF = m< EAF - (opposite vertical angles are equivalent)

2. m<BAC + m<EAC = 180 degrees (sum of linear pair)

3. m<CAB = 180 degrees - m<EAC

4. Equation 1: m<CAB = m<EAF = 119 degrees

5. m<EAF = m<EAD + m< DAF

6. m<EAD = m<EAF - m<DAF

7. m<EAD = 119 degrees-90 degrees = 29 degrees

Hope this helps!!! :)

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5 0
3 years ago
What is 57/6 simplified?
ludmilkaskok [199]
Answer:
19/2
Step-by-step explanation :
U divide the numerator and the denominator by the same number which is 3
57 divided by 3 = 19
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2 years ago
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Consider the first five steps of the derivation of the Quadratic Formula.
lara31 [8.8K]

Answer:

Full proof below

Step-by-step explanation:

\displaystyle ax^2+bx+c=0\\\\ax^2+bx=-c\\\\x^2+\biggr(\frac{b}{a}\biggr)x=-\frac{c}{a}\\\\x^2+\biggr(\frac{b}{a}\biggr)x+\biggr(\frac{b}{2a}\biggr)^2=-\frac{c}{a}+\biggr(\frac{b}{2a}\biggr)^2\\\\x^2+\biggr(\frac{b}{a}\biggr)x+\frac{b^2}{4a^2}=-\frac{c}{a}+\frac{b^2}{4a^2}\\ \\\biggr(x+\frac{b}{2a}\biggr)^2=-\frac{4ac}{4a^2}+\frac{b^2}{4a^2}\\ \\\biggr(x+\frac{b}{2a}\biggr)^2=\frac{b^2-4ac}{4a^2}\\ \\x+\frac{b}{2a}=\pm\frac{\sqrt{b^2-4ac}}{2a}\\ \\x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

6 0
1 year ago
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