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son4ous [18]
3 years ago
15

When did Confucius live? Ming dynasty Tao dynasty Chou dynasty Han dynasty

Social Studies
2 answers:
ipn [44]3 years ago
4 0

Answer:

chou dynasty

Explanation:

According to Records of the Historian, Confucius was born into a royal family of the Chou Dynasty.

Katen [24]3 years ago
3 0

Answer:

Confucius lived from September 28, 551 BC – April 11, 479 BC while the Chou (or Zhou) dynasty lasted from 1122–221 BC, so therefore, Confucius lived during the Chou dynasty

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One effect of the Alien and Sedition Acts was to limit the power of the Democratic Republican Party.  


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What should be done to prevent conlict in the society?​
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Following things should be done to prevent conflict in the society:-

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1) Do awareness program

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3) Give education to everyone

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People often learn through the study of Philosophy that they have been holding beliefs about themselves and about the world that
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A. True

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Brightburst believes that parents who do value vitamins represent excellent prospects. However, research suggests that many of t
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high in involvement

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26. A standard deck of playing cards consists of 52 cards, half of which are black and half of which are red. If three cards are
nlexa [21]

Answer:

1/4

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The probability of getting one black card out of a 52 deck of cards (where 26 are red and 26 are black) is: \frac{26}{52}, <u>(remember that probability of an event = (total amount of favorable outcomes/ total amount of outcomes)  </u>by simplifying this fraction we get: \frac{26}{52} = \frac{13}{26}=\frac{1}{2}.

Therefore, the probability of getting one black card out of a deck of 52  cards is 1/2.

Since the way of picking cards is done with replacement, for the <u>second card,</u> if we want to get another black one we would have a probability of <u>1/2.</u>

Again, for the <u>third card we would still have a probability of 1/2 of getting a black one.</u>

We want to get a black one on the first time AND on the second AND on the third one, therefore we have to use the rule of multiplication, which tells us we have to multiply all three probabilities:

P(having 3 black cards) = (\frac{1}{2}) (\frac{1}{2})(\frac{1}{2})= \frac{1}{8}

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P(having 3 red cards) =  (\frac{1}{2}) (\frac{1}{2})(\frac{1}{2})= \frac{1}{8}

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P(having 3 black cards OR 3 red cards) = \frac{1}{8} + \frac{1}{8}  = \frac{2}{8} = \frac{1}{4}

Thus, the probability that either all three are black or all three are red is 1/4

8 0
3 years ago
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