Question

HELP PLEASE: 40 POINTS

Answer 1

Answer:  The required match is

$\left(x^{-2},\dfrac{1}{9}\right);~\left(x^{-1},-\dfrac{1}{3}\right);~(x^0,1);~(x^1,-3),~(x^2,9).$

Step-by-step explanation:  We are given to match the following items with the given options by evaluating the expression for x = -3.

$x^{-2},~~x^{-1},~~x^0,~~x^1,~~x^2.$

We will be using the following property of exponents :

$a^{-b}=\dfrac{1}{a^b}.$

we have

$x^{-2}=\dfrac{1}{x^2}=\dfrac{1}{(-3)^2}=\dfrac{1}{9},\\\\\\x^{-1}=\dfrac{1}{x}=\dfrac{1}{(-3)}=-\dfrac{1}{3},\\\\\\x^0=1,\\\\\\x^1=x=-3,\\\\\\x^2=(-3)^2=9.$

Thus, the required match is

$\left(x^{-2},\dfrac{1}{9}\right);~\left(x^{-1},-\dfrac{1}{3}\right);~(x^0,1);~(x^1,-3),~(x^2,9).$

Answer 2

X^ -2: 1/9

x^ -1: -1/3

x^0: 1

x^1: -3

x^2: 9

Really hope this helped have a good day ;)