Answer:
2x² - 12x + 13
Step-by-step explanation:
Given following:
Start solving from right to left across the function.
Steps:
Answer:
The smallest power of 10 that will exceed
is
.
Step-by-step explanation:
We can use the following approach to determine the smallest power of 10 that will exceed M. We can transform that number into scientific notation, which is of the form:
, 
Where:
- Integer part, formed by a digit, which is of the highest order.
- Decimal part, formed by a digit onwards.
- Power grade.
The smallest power of 10 that will exceed M is 
If
, then, the power grade is number of spaces that dot must be moved leftwards. In this case, dot must be moved 5 spaces on the left. The integer part is 1 and the decimal part is 1852665902. Then, the value of
in scientific notation is:

Then, the smallest power of 10 that will exceed
is
.
Using the normal distribution, it is found that Sue will get a letter grade of B.
In a <em>normal distribution </em>with mean
and standard deviation
, the z-score of a measure X is given by:

- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem, Sue got a grade of 0.85, hence
.
- Looking at the z-table, z = 0.85 has a p-value of 0.8023, hence she is approximately in the top 20%, which is below the top 15% but above the top 50%, hence she got a letter grade of B.
A similar problem is given at brainly.com/question/25745464