The first 5 terms in an arithmetic sequence is 4,2,0,-2,-4
Explanation:
The general form of an arithmetic sequence is

where a denotes the first term of the sequence, d denotes the common difference.
Here a = 4 and d = -2
To determine the consecutive terms of the sequence, let us substitute the values for n.
To find the second term, substitute n = 2 in the formula 

Simplifying,

Similarly,
For n = 3,

For n = 4,

For n = 5,

Thus, the first 5 terms of the arithmetic sequence is 4,2,0,-2,-4
Answer:
<h2>11.1111111111 or 1.1 <-(rounded)</h2>
Step-by-step explanation:
4+6+7+7+11+12+15+18+20= 100
divide by the number of values we have. we have 9 values
100/9=11.1111111111
I hope this helped
Answer:
y=-5,x=2
Step-by-step explanation:
3x+3y=-9________________eqn 1
3x-3y=21________________eqn 2
using elimination method
3x+3y=-9
-
3x-3y=21
subtract equation 2 from equation 1
0+6y=-30
6y=-30
y=-30/6
y=-5
substitute the value of y in equation 1
3x+3y=-9
3x+3(-5)=-9
3x-15=-9
3x=-9+15
3x=6
x=6/3
x=2