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Ipatiy [6.2K]
3 years ago
8

What number and types of atoms occur in a formula unit of Ca(NO3),?

Chemistry
1 answer:
pav-90 [236]3 years ago
5 0

Answer:

help with mine ill help with yours

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Saltpeter is a compound made of potassium (k), nitrogen (n), and oxygen (o). every 100.00 g of saltpeter contains 38.67 g potass
xeze [42]
First, we need to compute the mass of oxygen found in 100 grams of saltpeter:
mass of oxygen = 100 - (mass of potassium + mass of nitrogen)
                          = 100 - (38.67 + 13.86)
                          = 100 - 52.53
mass of oxygen in 100 grams saltpeter = 47.47 grams

Now, we can use cross multiplication to find the mass of oxygen in 328 grams saltpeter as follows:
mass of oxygen = (328 x 47.47) / 100 = 155.7016 grams
5 0
3 years ago
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Which of the following statements is accurate
Rufina [12.5K]
A. If an objects velocity is decreasing, the object is said to be decelerating not accelerating.
B. If an objects velocity changes, it is either experiencing acceleration or deceleration 
C. If an object is said to be decelerating, its velocity must be decreasing.
D. If an objects velocity remains constant, its acceleration is zero. 

∴ B is correct
3 0
4 years ago
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Stirring a liquid while you are mixing in another ingredient speeds up the rate of dissolving. Question 13 options: True False
brilliants [131]

Answer:

true

Explanation:

This is because it helps distribute the particles that are being dissolved. 

8 0
3 years ago
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How many moles of hydrogen are required to make 32 moles of water?
NNADVOKAT [17]
You multiply 32 by 2, since there are two hydrogens in every water molecule.
7 0
4 years ago
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The theoretical yield of a reaction is the amount of product obtained if the limiting reactant is completely converted to produc
Elis [28]

Answer: 9.9 grams

Explanation:

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

a) moles of H_2

\text{Number of moles}=\frac{8.150g}{2g/mol}=4.08moles

b) moles of C_2H_4

\text{Number of moles}=\frac{9.330g}{28g/mol}=0.33moles

H_2(g)+C_2H_4(g)\rightarrow C_2H_6(g)

According to stoichiometry :

1 mole of C_2H_4 combine with 1 mole of H_2

Thus 0.33 mole of C_2H_4 will combine with =\frac{1}{1}\times 0.33=0.33 mole of H_2

Thus C_2H_4 is the limiting reagent as it limits the formation of product.

As 1 mole of C_2H_4 give =  1 mole of C_2H_6

Thus 0.33 moles of C_2H_4 give =\frac{1}{1}\times 0.33=0.33moles  of C_2H_6

Mass of C_2H_6=moles\times {\text {Molar mass}}=0.33moles\times 30g/mol=9.9g

Thus theoretical yield (g) of C_2H_6 produced by the reaction is 9.9 grams

7 0
3 years ago
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