To form CuO - 100 g of Copper reacts with 25 g of Oxygen
then amount of CuO formed - 125 g
Since excess oxygen is provided, Copper is the limiting reactant. Then Copper is completely consumed during the reaction and amount of product formed depends on the amount of Copper used.
So if 100 g of Copper makes up 125 g of CuO
Then 140 g of Copper will form - 125/100 x 140 = 175 g of CuO
PCL5[l]+4H2O=H3PO4+5HCL
CHECK;
on the L.H.S
P=1
CL=5
H=8
O=4
On the R.H.S
P=1
CL=5
H=8
O=4
is the solubility of the gas when it exerts a partial pressure of 92.4kPa.
<h3>What is Henry's law?</h3>
Mathematically, we can get this from Henry's law
From Henry law;
Concentration = Henry constant × partial pressure
Thus Henry constant =
Henry constant =
Hence, is the solubility of the gas when it exerts a partial pressure of 92.4kPa.
Learn more about the Henry's law here:
brainly.com/question/16222358
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I know for number 4 the answer is c, sorry I can't help with the others.