During an effusion experiment, a certain number of moles of an unknown gas passed through a tiny hole in 50 seconds. Under the s
1 answer:
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Sodium carbonate is used to neutralised sulfuric acid, H₂SO₄. Sodium carbonate is the salt of stron base (NaOH) and weak acid (H₂CO₃). The balanced chemical reaction for neutralization is as follows:
Na₂CO₃ + H₂SO₄→ Na₂SO₄ + H₂CO₃
From balanced chemical equation, it is clear that one mole of Na₂CO₃ is required to neutralize one mole of H₂SO₄. Molar mass of Na₂CO₃= 106 g/mol=0.106 kg/mol and molar mass of H₂SO₄= 98 g/mol=0.098 kg/mol.
To neutralize 0.098 kg of H₂SO₄ amount of Na₂CO₃ required is 0.106 kg, so, to neutralize 5.04×10³ kg of H₂SO₄, Na₂CO₃ required is= kg= 5.451 X 10³ kg.
Answer:
<h2>1.89 atm</h2>Explanation:
The new volume can be found by using the formula for Boyle's law which is
Since we are finding the new volume
From the question we have
We have the final answer as
<h3>1.89 atm</h3>Hope this helps you
Answer :
AgBr should precipitate first.
The concentration of when CuBr just begins to precipitate is,
Percent of remains is, 0.0018 %
Explanation :
for CuBr is
for AgBr is
As we know that these two salts would both dissociate in the same way. So, we can say that as the Ksp value of AgBr has a smaller than CuBr then AgBr should precipitate first.
Now we have to calculate the concentration of bromide ion.
The solubility equilibrium reaction will be:
The expression for solubility constant for this reaction will be,
Now we have to calculate the concentration of silver ion.
The solubility equilibrium reaction will be:
The expression for solubility constant for this reaction will be,
Now we have to calculate the percent of remains in solution at this point.
Percent of remains =
Percent of remains = 0.0018 %