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3 years ago

Simply the expression -2.2f+0.9f-14-8

Mathematics

2 answers:

Lady bird [3.3K]3 years ago

6 0

Answer:

-1.3f-22

please mark brainliest :))))))

Step-by-step explanation:

Marianna [84]3 years ago

6 0

Answer:

-1.3 - 6

Step-by-step explanation:

combine -2.2 and 0.9, since 0.9 is positive and -2.2 is negative the answer is -1.3, then simply subtract 14-8.

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inessss [21]

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4 years ago

Factorise the following using the Difference of Two Squares or Perfect Squares rule: a) (2x-2)^2 - (x+4)^2 b) (3x+4) (3x-4)

emmainna [20.7K]

Answer:

Step-by-step explanation:

Hello, please consider the following.

$(2x-2)^2 - (x+4)^2 \\\\=(2x-2-(x+4))(2x-2+x+4)\\\\=(2x-2-x-4)(3x+2)\\\\=\boxed{(x-6)(3x+2)}$

$(3x+4) (3x-4)\\\\=(3x)^2-4^2\\\\=\boxed{9x^2-16}$

Thank you.

7 0

3 years ago

Bob and Dave go to PizzaScoff. Starting with 35 pizzas, Bob eats 6 4/5 pizzas and Dave eats 8 1/3 pizzas. How many are left?

Ray Of Light [21]

Answer:

19.87 Pizzas are left

Step-by-step explanation:

To solve, just take 35 the number of starting pizzas and then subtract the number pizzas both of them consumed. So, 35 - 6.8 given 4/5 converts to 0.8 this leaves use with Bob's pizza consumption only at 28.2 pizza's left. Next, we are going to take 28.2 - 8.33 given 1/3 is .3333 repeating this then gives us the answer with having 19.87 pizzas left - although if it asks how many whole pizzas you would say 28 given you can't have .87 of a pizza.

7 0

3 years ago

Some whole numbers are irrational numbers? True or False?

Mariulka [41]

Answer:

False. Whole numbers are actually Rational Numbers.

I hope that helps u!!!

7 0

3 years ago

Read 2 more answers

Suppose that the trace of a 2×2 matrix a is tr(a)=15 and the determinant is det(a)=50. find the eigenvalues of

IrinaK [193]

Recall that the characteristic polynomial of a 2x2 matrix $\mathbf A=\begin{bmatrix}a&b\\c&d\end{bmatrix}$ is

$\det(\mathbf A-\lambda\mathbf I)=\begin{vmatrix}a-\lambda&b\\c&d-\lambda\end{vmatrix}=(a-\lambda)(d-\lambda)-bc=\lambda^2-(a+d)\lambda+(ad-bc)$

but $\det(\mathbf A)=ad-bc$ and $\mathrm{tr}(\mathbf A)=a+d$ , so the characteristic polynomial for $\mathbf A$ is

$\lambda^2-\mathrm{tr}(\mathbf A)\lambda+\det(\mathbf A)$

We're given that the trace is 15 and determinant is 50, so the characteristic polynomial for the matrix in question is

$\lambda^2-15\lambda+50$

and the eigenvalues are those $\lambda$ for which the characteristic polynomial evaluates to 0.

$\lambda^2-15\lambda+50=(\lambda-5)(\lambda-10)=0\implies\lambda=5,\lambda=10$

5 0

3 years ago