Answer:
Attachment
Step-by-step explanation:
x = 0
y = | 0 + 4 | - 1
y = 4 - 1
y = 3
y = 0
0 = | x + 4 | - 1
1 = | x + 4 |
x + 4 = 1 => x₁ = 1 - 4 => x₁ = - 3
x + 4 = - 1 => x₂ = - 1 - 4 => x₂ = - 5
<span>Let the number of chairs in a row be x, then the total number of chairs is 9x + 3 = 7x + 19. i.e. 9x + 3 = 7x + 19; 9x - 7x = 19 - 3; 2x = 16 x = 16/2 = 8. Thus there are 8 chairs in each row. Therefore, the total number of chairs is given by 9(8) + 3 = 72 + 3 = 75.I hope that my answer is helpful! Let me know if you need something more :)</span>
Answer:
The length of the rectangle = 63 ft
Step-by-step explanation:
Let us assume the width of the rectangle = m ft
So, the length of the rectangle = 3 x Width = 3 x m = 3 m ft
Perimeter = 168 ft
PERIMETER OF A RECTANGLE = 2 (LENGTH + WIDTH)
⇒ 168 ft = 2 ( 3 m + m)
or, 168 = 2 ( 4 m)
or, 8 m = 168
⇒ m = 168/8 = 21
or, m = 21 ft
Hence, the width of the rectangle = m = 21 ft
And the length of the rectangle = 3 x m = 3 x 21 = 63 ft
Answer:
m∠A=59
Step-by-step explanation:
There are 180° in a triangle.
A+B+C=180
A+99+22=180
A+121=180
A=59
Answer:
The number of rainfalls is 
The answer to the second question is no it will not be valid this because from the question we are told that the experiment require one pH reading per rainfall so getting multiply specimens(used for the pH reading) from one rainfall will make the experiment invalid.
Step-by-step explanation:
from the question we are told that
The standard deviation is 
The margin of error is 
Given that the confidence level is 95% then we can evaluate the level of significance as



Next we will obtain the critical value of
from the normal distribution table , the value is 
Generally the sample size is mathematically represented as
![n = [\frac{Z_{\frac{\alpha }{2} * \sigma }}{ E} ]^2](https://tex.z-dn.net/?f=n%20%20%3D%20%20%5B%5Cfrac%7BZ_%7B%5Cfrac%7B%5Calpha%20%7D%7B2%7D%20%2A%20%20%5Csigma%20%7D%7D%7B%20E%7D%20%5D%5E2)
substituting values
![n = [\frac{1.96 * 0.5 }{ 0.1} ]^2](https://tex.z-dn.net/?f=n%20%20%3D%20%20%5B%5Cfrac%7B1.96%20%2A%200.5%20%7D%7B%200.1%7D%20%5D%5E2)

The answer to the second question is no the validity is null this because from the question we are told that the experiment require one pH reading per rainfall so getting multiply specimens(used for the pH reading) from one rainfall will make the experiment invalid