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IceJOKER [234]
2 years ago
10

If 317 + x = 609 then,

Mathematics
1 answer:
diamong [38]2 years ago
7 0

Answer:

E

Step-by-step explanation:

subtract 317 from 609.

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Which cylinder pressure will Jillian need if she plans to fill 90 balloons?
LiRa [457]

Answer:

C

Step-by-step explanation:

Because if she wants to fill 90 balloons 100 is 30 so multiply by 30×3 and u get 90

5 0
3 years ago
Complete the proof in picture
BARSIC [14]

it won't let me type the answer I may be missing something but it says I am using rude words so sorry if I am

5 0
3 years ago
Find the base of an isosceles triangle whose area is 60 cm² and the length of one of its equal sides is 13 cm. ​
Kobotan [32]

Answer:

Base = 24 cm or 10cm

Step-by-step explanation:

REMEMBER:
An isosceles triangle ABC with base BC = ‘b' & height AD = ‘h' & its equal sides =13 cm & area = 60 cm²

Using the formulas

A=\frac{bh_b}{2}

h_b=\sqrt{a^2-\frac{b^2}{4} }

There are 2 solutions for b

b=2\sqrt{2}   \frac{A}{\sqrt{a^2+\sqrt{a^4-4A^2} } } =2*\sqrt{2} *\frac{60}{\sqrt{13^2+\sqrt{13^4-4*60^2} } } ≈ 10cmb=2\sqrt{2}   \frac{A}{\sqrt{a^2+\sqrt{a^4-4A^2} } } =2*\sqrt{2} *\frac{60}{\sqrt{13^2-\sqrt{13^4-4*60^2} } }=24cm

Less complex:

Area of a triangle = 1/2 * b * h = 60

=> h = 120/b

In right triangle ABD

13² = h² + b² /4 ( by Pythagoras law)

=>169 = 120²/b² + b²/4

=>676 b² = 57600 + b^4

=> b^4 - 676 b² + 57600 = 0

=> b² = 676 +- √(676² - 4*57600) / 2

=> b²= 676 +- √(226576) /2

=> b² = (676 +- 476 )/2

=> b² = 1152/2 , 200 /2

=> b² = 576 , 100

=> b = 24, 10

So, Base = 24 cm or 10cm

4 0
1 year ago
Henry and reiko both used 1 yard of ribbon to make bows. write two different fractions to show that Henry and reiko use the same
Natalka [10]
To show that they used the same amount of ribbon you could take the 1 yard and divided into different sized equal groups.

1 yard divided by four equals 1/4 yard for each of four ribbons.

1 yard divided by six equals 1/6 yard for each of six ribbons.

You could have ribbons the size of 1/4 our yard and 1/6 yard, but you would have different amounts of each.
4 0
3 years ago
Compute and compare the side lengths of the two figures. Does this support an argument claiming that they are congruent? What el
Sunny_sXe [5.5K]
We compute for the side lengths using the distance formula √[(x₂-x₁)²+(y₂-y₁)²].

AB = √[(-7--5)²+(4-7)²] = √13
A'B' = √[(-9--7)²+(0-3)²] = √13

BC = √[(-5--3)²+(7-4)²] = √13
B'C' = √[(-7--5)²+(3-0)²] =√13

CD = √[(-3--5)²+(4-1)²] = √13
C'D' = √[(-5--7)²+(0--3)²] = √13

DA = √[(-5--7)²+(1-4)²] = √13
D'A' = √[(-7--9)²+(-3-0)²] = √13

The two polygons are squares with the same side lengths. 

But this is not enough information to support the argument that the two figures are congruent. In order for the two to be congruent, they must satisfy all conditions: 
1. They have the same number of sides.
2. All the corresponding sides have equal length.
3. All the corresponding interior angles have the same measurements.

The third condition was not proven.
6 0
3 years ago
Read 2 more answers
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