Answer:
280 i believe
Step-by-step explanation:
5 x 7 x 8 = 280
The question is incomplete. Here is the complete question:
Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.95 probability that he will hit it. One day, Samir decides to attempt to hit 10 such targets in a row.
Assuming that Samir is equally likely to hit each of the 10 targets, what is the probability that he will miss at least one of them?
Answer:
40.13%
Step-by-step explanation:
Let 'A' be the event of not missing a target in 10 attempts.
Therefore, the complement of event 'A' is 
Now, Samir is equally likely to hit each of the 10 targets. Therefore, probability of hitting each target each time is same and equal to 0.95.
Now, 
We know that the sum of probability of an event and its complement is 1.
So, 
Therefore, the probability of missing a target at least once in 10 attempts is 40.13%.
60.
The question gives you the fact that 6 bricks is 2 feet high.
What do you do to get from 2 to 20?
You multiply by 10.
Since you multiplied one thing by 10, you must do it to the other side so it remains balanced.
2 ft x 10ft = 20ft
6 bricks x 10 bricks = 60 bricks
The image of the car park showing the 2 angles is attached.
Answer:
Their lines are parallel.
Step-by-step explanation:
From the attached image, we can see that ∠1 and ∠2 form a pair of alternate exterior angles. Thus; ∠1 = ∠2.
Now since they are congruent, it means that their lines will be parallel.
Thus, we can conclude that their lines are parallel.
Answer:
We can have two cases.
A quadratic function where the leading coefficient is larger than zero, in this case the arms of the graph will open up, and it will continue forever, so the maximum in this case is infinite.
A quadratic function where the leading coefficient is negative. In this case the arms of the graph will open down, then the maximum of the quadratic function coincides with the vertex of the function.
Where for a generic function:
y(x) = a*x^2 + b*x + c
The vertex is at:
x = -a/2b
and the maximum value is:
y(-a/2b)