Question

Determine the amplitude or period as requested. Period of y = - 1/3 * sin 2x

Answer 1

Answer:

$Period = \pi$

Step-by-step explanation:

Given

$y = -\frac{1}{3} * \sin(2x)$

Required

The period

A sine function is represented as:

$y =A \sin(Bx + C) + D$

Where

$Period = \frac{2\pi}{B}$

By comparing:

$y =A \sin(Bx + C) + D$ and $y = -\frac{1}{3} * \sin(2x)$

$B = 2$

So, we have:

$Period = \frac{2\pi}{2}$

$Period = \pi$

Hence, the period of the function is $\pi$