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anzhelika [568]
3 years ago
13

Pls show work I need the work. Thx

Mathematics
1 answer:
Ainat [17]3 years ago
5 0
Sorry i can’t quite see the image can you do another one
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How do i solve this?
Marizza181 [45]

Answer:

Step-by-step explanation:

5x10x8 / 26400 = 0.00909090909

/ means divide

hope it helps

6 0
3 years ago
A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. ​(a) Describe the
Ivanshal [37]

Answer:

a) \bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})

With:

\mu_{\bar X}= 83

\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3

b) z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2

P(Z>2) = 1-P(Z

c) z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45

P(Z

d) z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1

z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2

P(-1.2

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

\mu = 83, \sigma = 27

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})

With:

\mu_{\bar X}= 83

\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3

Part b

We want this probability:

P(\bar X>89)

We can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 89 we got:

z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2

P(Z>2) = 1-P(Z

Part c

P(\bar X

We can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 75.65 we got:

z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45

P(Z

Part d

We want this probability:

P(79.4 < \bar X < 89.3)

We find the z scores:

z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1

z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2

P(-1.2

8 0
4 years ago
A flash disk has the capacity of storing 1 megabyte of data. How many kilobytes of data can be stored in the same flash disk​
Luden [163]

For this sort of problem, you need to be familiar with prefixes.

So:

megabyte = 1 *10^6 bytes

kilobyte = 1*10^3 bytes

and a regular byte would just be 1

Now, you will need to do a conversion:

1megabyte*\frac{1*10^6bytes}{1megabyte}*\frac{1*10^{-3}kilobyte}{1byte}

I'm going to explain this just in case, but we convert megabytes to regular bytes in the first half by using the information I gave you above. (In one megabyte, there are 1*10^6 bytes!)

In the second fraction thought, remember one kilobyte is 1*10^3 bytes. However, you usually only see one of each thing on the bottom of fractions, so you need to add a negative sign to the 3. (technically you could just do \frac{1kilobyte}{1*10^3bytes}, but I think it is more correct to do write it out how I did).

*** They do equal the same thing though! Do whichever way is easier for you!

Now, your answer should be:

10^3 kilobytes (1000 kilobytes)

Hope this helped!

6 0
3 years ago
A park is in the shape of a parallelogram. The park has an area of 776.25 square yards. The base of the park is 34.5 yards. mart
stich3 [128]

Answer:

The height is given by: 776.5 / 34.5 = about 22.5 yards. So....10 times this is about 225 yards.

3 0
4 years ago
Help me thank you!!!!
Marat540 [252]

Answer:

Step-by-step explanation:

<1 = <5                              Corresponding angles.

<5 + <6 = 180°                  Angles making up the same straight line are supplementary.

<1 + <6 = 180°                   <1 and <5 are equal.

<6 = 180° - <1                    If we know <1 we can easily find six. It is <1s supplement.

5 0
3 years ago
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