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lord [1]
3 years ago
11

Prove if the sum of the digits of a 3 digit number n is divisible by 9, then n is divisible by 9.

Mathematics
1 answer:
beks73 [17]3 years ago
6 0

n=100x+10y+z\\x+y+z=9k,k\in\mathbb{Z}\\\\n=99x+9y+x+y+z\\n=99x+9y+9k\\n=9(11x+y+k)

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What is the solution to 9e-7=7e-11<br> need it now
oee [108]

The answer is e = -2

I hope this helped! If so, please mark brainliest!

Step by step solution :

Step  1  :

Pulling out like terms :

1.1     Pull out like factors :

  2e + 4  =   2 • (e + 2)  

Equation at the end of step  1  :

Step  2  :

Equations which are never true :

2.1      Solve :    2   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

2.2      Solve  :    e+2 = 0  

Subtract  2  from both sides of the equation :  

                     e = -2

8 0
3 years ago
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In God's redemptive plan for mankind, the Feast of Weeks was a "shadow" or "type" of:
navik [9.2K]

Answer:

burnt offerings

Step-by-step explanation:

3 0
4 years ago
Flower bed has the shape of a rectangle 24 ft long and 9 ft wide what is the area in square yards
natali 33 [55]
The answer is 24 square yards
24ft=8yd
9ft=3yd
So 8*3=24 square yard

Hope this helps
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4 years ago
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ДОПОМОЖІТЬ, БУДЬ ЛАСКА !!!! МАТЕМАТИКА !!!!!!!!
ivann1987 [24]
Plot a point at the Y-Intercept of -1 and Plot another point at the X-intercept of 1 and the DIGITS graphing tool should make a line from there


6 0
4 years ago
Please help!! This is so confusing! 100 points!!
masya89 [10]

Answer:

The value of the expression given is:

  • 4

Step-by-step explanation:

First, you must divide the expression in three, and to the final, you can multiply it:

  1. [(3^8)*(2^(-5))*(9^0)]^(-2)
  2. [(2^(-2))/(3^3)]^4
  3. 3^28

Now, we can solve each part one by one:

<em>First part. </em>

  • 3^8 = 6561
  • 2^(-5) = 0.03125
  • 9^0 = 1 (Whatever number elevated to 0, its value is 1)
  • (6561 * 0,03125 * 1) = 205.03125

And we elevate this to -2:

  • 205.03125^-2 = 2<u>.378810688*10^(-5)</u> or <u>0.00002378810688 </u>

<em>Second part. </em>

  • 2^(-2) = 0.25
  • 3^3 = 27
  • 0.25 / 27 = 9.259259259 * 10^(-3) or 0.00925925925925

And we elevate this to 4:

  • 0.00925925925925^4 = <u>7.350298528 * 10^(-9)</u> or <u>0.000000007350298528 </u>

<em>Third Part. </em>

  • 3^28 = <u>2.287679245 * 10^13</u> or <u>22876792450000</u>

At last, we multiply all the results obtained:

  • 0.00002378810688 * 0.000000007350298528 * 22876792450000 = <u>3.999999999999999999</u> approximately <u>4</u>

<u><em>We approximate the value because the difference to 4 is minimal, which could be obtained if we use all the decimals in each result</em></u>.

3 0
3 years ago
Read 2 more answers
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