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Anika [276]
3 years ago
15

The video store just increased the price of renting a game by 1.25. Write a formula that will help Seth determine how much he'll

spend at the video game store after the price increase. Let's let p = old price of a video game, n = number of games Seth rents & t = total amount Seth pays.
Mathematics
1 answer:
givi [52]3 years ago
6 0

First you would need to add the amount of the increase to the old price , so that would be p +1.25.

Then to find the total amount he will spend, you need to multiply the total price by the number of games he buys.

The equation becomes:

t = n(p+1.25)

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Need help with this ASAP it’s due in 10 minutes
Gennadij [26K]

Answer:

Step-by-step explanation:

Formula to be used,

A = P(1+\frac{r}{n})^{nt}

Here, A = Final amount

P = Principal amount

r = rate of interest

n = Number of compounding (In a year)

t = Duration of investment (In years)

Question (5)

P = $4250

r = 0.015

n = 4

t = 3 years

A = 4250(1+\frac{0.015}{4})^{4\times 3}

A = 4250(1.00375)^{12}

A = $4445.24

Part (C)

1). P = $6000

   r = 0.03

   n = 2

   t = 10 years

  A = 6000(1+\frac{0.03}{2})^{2\times 10}

      = 6000(1.015)^{20}

      = $8081.13

2). P = $9000

    r = 0.05

    n = 2

    t = 8 years

    A = 9000(1+\frac{0.05}{2})^{2\times 8}

        = 9000(1.025)^{16}

        = $13360.55

5 0
3 years ago
MARKING AS BRAINLIEST
Valentin [98]

Answer:

I got 22.4

Step-by-step explanation:

I used the formula A=1/2bh

A=1/2(8)5.6

A=4(5.6)

A=22.4

5 0
3 years ago
If y varies directly as x and y = 15 when x = 5,what is the value of y when x = 6? a. 5 b. 36 c. 9 d. 18
Evgesh-ka [11]
The answer to this question is D
8 0
4 years ago
A baker uses 2/3 of a canister of flour to bake 4 loaves of bread. How much flour does the baker use to bake 3 loaves of bread?
andrew11 [14]
3/6 canister or one half canister because 2 loaves is 1/3 and 1 loaf is 1/6 so (1/6 x 3)=3/6
7 0
4 years ago
how many gallons of 80% antifreeze solution must be mixed with 100 gallons of 10% antifreeze to get a mixture that is 70% antifr
ololo11 [35]
Let's say we'll mix "x" amount of the 80% solution, how much antifreeze is in it? well is just 80% of antifreeze, and the rest is something else.... what's 80% of "x"? so is (80/100)*x, or 0.8x.

likewise, the mixture will be a 70% solution, and let's say it adds up to "y" amount, so how much antifreeze is in it? well (70/100) * y or 0.7y.

\bf \begin{array}{lccclll}
&\stackrel{gallons}{amount}&\stackrel{\%}{quantity}&\stackrel{antifreeze}{quantity}\\
&------&------&------\\
\textit{80\% sol'n}&x&0.80&0.8x\\
\textit{10\% sol'n}&100&0.10&10\\
------&------&------&------\\
mixture&y&0.70&0.7y
\end{array}

so whatever "x" is, we know that x + 100 = y.

and we know that 0.8x + 10 = 0.7y.

\bf \begin{cases}
x+100=\boxed{y}\\
0.8x+10=0.7y\\
----------\\
0.8x+10=0.7\left( \boxed{x+100} \right)
\end{cases}
\\\\\\
0.8x+10=0.7x+70\implies 0.8x-0.7x=70-10\implies 0.1x=60
\\\\\\
x=\cfrac{60}{0.1}\implies x=600
6 0
3 years ago
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