Answer:
Increased processor speed and multi core technologies.
Explanation:
The development of processors over the years is overwhelmingly fast. The CPU use to be cumbersome, expensive and computational speed was moderate.
As it evolves, the CPU was minimized to give rise to microprocessors.
Microprocessors are very fast, running millions of processes on its core. The multiple core processors helped to increase the speed of these processors.
When there are more than one core in a processor (dual, quad or octal core), it processes data in parallel reducing the time of execution compared to a one core processor.
A company having computers with single core would need to upgrade to a new computer with multi core processor to promote speed in data processing.
Answer:
B and C
Explanation:
xPos and yPos determine the center of the circle, and rad determines the radius of the circle drawn.
It cannot be A because it starts drawing a circle with the center of (4, 1). None of the circles ahve a center at (4, 1). It is B because while it does start at (4, 1), the repeat function adds one to the y and radius. While ti repeats 3 times it ends up drawing all 3 circles. C also works because it starts by drawing the biggest circle and then subtracting the values to make the other two. It cannot be D because in the repeat function it subtracts from the y value and radius too early, it doesn't draw the biggest circle.
Answer
The answer and procedures of the exercise are attached in the following archives.
Step-by-step explanation:
You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.
Answer:
a) Yes
b) Yes
c) Yes
d) No
e) Yes
f) No
Explanation:
a) All single-bit errors are caught by Cyclic Redundancy Check (CRC) and it produces 100 % of error detection.
b) All double-bit errors for any reasonably long message are caught by Cyclic Redundancy Check (CRC) during the transmission of 1024 bit. It also produces 100 % of error detection.
c) 5 isolated bit errors are not caught by Cyclic Redundancy Check (CRC) during the transmission of 1024 bit since CRC may not be able to catch all even numbers of isolated bit errors so it is not even.
It produces nearly 100 % of error detection.
d) All even numbers of isolated bit errors may not be caught by Cyclic Redundancy Check (CRC) during the transmission of 1024 bit. It also produces 100 % of error detection.
e) All burst errors with burst lengths less than or equal to 32 are caught by Cyclic Redundancy Check (CRC) during the transmission of 1024 bit. It also produces 100 % of error detection.
f) A burst error with burst length greater than 32 may not be caught by Cyclic Redundancy Check (CRC) during the transmission of 1024 bit.
Cyclic Redundancy Check (CRC) does not detect the length of error burst which is greater than or equal to r bits.
Answer:
Target area range is a survey of what lies about 12-20 seconds ahead of the vehicle. Correct Answer is B. (10-20 second)
Explanation:
Target area range is the space between your vehicle and the target area. A target area is an area on the roadway where the target is located. A target can be anything such as a car, a traffic signal, a blackhead, etc.
Target area range is also a section of roadway where the target is located and the area to the left and right of the target area
