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Irina18 [472]
3 years ago
9

Water freezes at 0 degrees Celsius. A student discovered that adding half a cup of salt to a gallon of water lowers its freezing

temperature by 7 degrees Celsius. What is the freezing temperature of the gallon of salt water?
Mathematics
1 answer:
Artemon [7]3 years ago
4 0

Answer:

-7°C

Step-by-step explanation:

Freezing point of water = 0°C

By adding salt, freezing point lowers by 7°C ;

The freezing point of salt water can be expressed as ;

Since temperature lowers :

Freezing point of salt water :

Freezing point of water - 7°C

0°C - 7°C

= - 7°C

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Sergeeva-Olga [200]

Answer:

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Answer:

down below:)

Step-by-step explanation:

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3 years ago
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An expression, that is a function, will have no x-repeats on the x,y pairs.

and expression that is a function, and has an inverse that is also a function, will have no x-repeats, and no y-repeats either, so the pairs will be unique for the set, let's do some checking then,

\bf a \qquad\{(-1, 3), (0, 4), (1, 14), (5, 6), (7, 2)\}\\\\&#10;b \qquad\{(-1, 2), (0, \stackrel{\downarrow }{4}), (1, 5), (5, \stackrel{\downarrow }{4}), (7, 2)\}\impliedby &#10;\begin{array}{llll}&#10;\textit{notice the } y-rep eats\\&#10;\textit{thus, no dice}&#10;\end{array}

\bf c \qquad\{(-1, -2), (0, \stackrel{\downarrow }{4}), (1, 3), (5, 14), (7, \stackrel{\downarrow }{4})\}\impliedby &#10;\begin{array}{llll}&#10;\textit{notice the } y-rep eats\\&#10;\textit{thus, no dice}&#10;\end{array}\\\\&#10;d \qquad\{(-1, \stackrel{\downarrow }{4}), (0, \stackrel{\downarrow }{4}), (1, 2), (5, 3), (7, 1)\}\impliedby &#10;\begin{array}{llll}&#10;\textit{notice the } y-rep eats\\&#10;\textit{thus, no dice}&#10;\end{array}
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