if a motercycle is moving at a constant speed down the highway of 40 km/hr, how long would it the motorcycle to travel 10 km
1 answer:
Answer:
15 minutes
Step-by-step explanation:
First, the motorcycle goes at a speed of 40 km/hr.
The question asks for how long it would take to travel 10 km.
Well, there are 60 minutes in an hour, since we will be translating into minutes.
Also, 10 km is 1/4 of 40 km, so it would make sense that the time length would be 1/4 of an hour as well.
1/4 of 60 minutes is 15 minutes. So it takes 15 minutes for the motorcycle to travel 10 km.
Now, if all this wordy stuff is too much to comprehend, you can also solve using proportional relationships.
Now cross multiply:
Divide both sides by 40:
Again, this shows that it wouls take 15 minutes for the motorcycle to travel 10 km.
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Answer/Step-by-sep explanation:
To determine whether the lines given in each box are parallel, perpendicular, or neither, take the following simple steps:
1. Ensure the equations for both lines being compared are in the slope-intercept form, y = mx + b. Where m is the slope.
2. If both lines have the same slope value, m, then both lines are parallel.
3. If the slope of one line is the negative reciprocal of the other, then both lines are perpendicular. That is, x = -1/x.
4. If the slope of both lines are not the same, nor the negative reciprocal of each other, then they are neither parallel nor perpendicular.
1. y = 3x - 7 and y = 3x + 1.
Both have the same slope value of 3. Therefore, they are parallel.
2. ⬜ and
The slope of both lines are not the same, nor is the slope of one the negative reciprocal of the other. The slope of one is -⅖ and the slope of the other is ⅖. Therefore, they are neither parallel nor perpendicular.⬜
3. and
The slope of the first line, ¼, is the negative reciprocal of the slope of the second line, 4.
Therefore, they are perdendicular.
4. 2x + 7y = 28 and 7x - 2y = 4.
Rewrite both equations in the slope-intercept form, y = mx + b.
2x + 7y = 28
7y = -2x + 28
y = -2x/7 + 28/7
y = -²/7 + 4
And
7x - 2y = 4
-2y = -7x + 4
y = -7x/-2 + 4/-2
y = ⁷/2x - 2
The slope of the first line, -²/7, is the negative reciprocal of the slope of the second line, ⁷/2.
Therefore, they are perdendicular.
5.⬜ y = -5x + 1 and x - 5y = 30.
Rewrite the second line equation in the slope-intercept form.
x - 5y = 30
-5y = -x + 30
y = -2x/-5 + 30/-5
y = ⅖x - 6
The slope of both lines are not the same, nor is the slope of one the negative reciprocal of the other. The slope of one is -5 and the slope of the other is ⅖. therefore, they are neither parallel nor perpendicular.⬜
6.⬜ 3x + 2y = 8 and 2x + 3y = -12.
Rewrite both line equations in the slope-intercept form.
3x + 2y = 8
2y = -3x + 8
y = -3x/2 + 8/2
y = -³/2x + 4
And
2x + 3y = -12
3y = -2x -12
y = -2x/3 - 12/3
y = -⅔x - 4
The slope of both lines are not the same, nor is the slope of one the negative reciprocal of the other. The slope of one is -³/2 and the slope of the other is -⅔ therefore, they are neither parallel nor perpendicular.⬜
7. y = -4x - 1 and 8x + 2y = 14.
Rewrite the equation of the second line in the slope-intercept form.
8x + 2y = 14
2y = -8x + 14
y = -8x/2 + 14/2
y = -4x + 7
Both have the same slope value of -4. Therefore, they are parallel.
8.⬜ x + y = 7 and x - y = 9.
Rewrite the equation of both lines in the slope-intercept form.
x + y = 7
y = -x + 7
And
x - y = 9
-y = -x + 9
y = -x/-1 + 9/-1
y = x - 9
The slope of both lines are not the same, nor is the slope of one the negative reciprocal of the other. The slope of one is -1, and the slope of the other is 1, therefore, they are neither parallel nor perpendicular.⬜
9. y = ⅓x + 9 And x - 3y = 3
Rewrite the equation of the second line.
x - 3y = 3
-3y = -x + 3
y = -x/-3 + 3/-3
y = ⅓x - 1
Both have the same slope value of ⅓. Therefore, they are parallel.
10.⬜ 4x + 9y = 18 and y = 4x + 9
Rewrite the equation of the first line.
4x + 9y = 18
9y = -4x + 18
y = -4x/9 + 18/9
y = -⁴/9x + 2
The slope of both lines are not the same, nor is the slope of one the negative reciprocal of the other. The slope of one is -⁴/9, and the slope of the other is 4, therefore, they are neither parallel nor perpendicular.⬜
11.⬜ 5x - 10y = 20 and y = -2x + 6
Rewrite the equation of the first line.
5x - 10y = 20
-10y = -5x + 20
y = -5x/-10 + 20/-10
y = ²/5x - 2
The slope of both lines are not the same, nor is the slope of one the negative reciprocal of the other. The slope of one is ⅖, and the slope of the other is -2, therefore, they are neither parallel nor perpendicular.⬜
12. -9x + 12y = 24 and y = ¾x - 5
Rewrite the equation of the first line.
-9x + 12y = 24
12y = 9x + 24
y = 9x/12 + 24/12
y = ¾x + 2
Both have the same slope value of ¾. Therefore, they are parallel.
Answer:
a) k = 5; (-10, -35)
Step-by-step explanation:
Given:
Co-ordinates:
Pre-Image = (-12,3)
After dilation
Image = (-60,15)
The dilation about the origin can be given as :
Pre-Image
where represents the scalar factor.
We can find value of for the given co-ordinates by finding the ratio of
or
co-ordinates of the image and pre-image.
For the given co-ordinates.
Pre-Image = (-12,3)
Image = (-60,15)
The value of
or
As we get for both ratios i.e of
and
co-ordinates, so we can say the image has been dilated by a factor of 5 about the origin.
To find the image of (-2,-7), after same dilation, we will multiply the co-ordinates with the scalar factor.
Pre-Image Image
Pre-Image Image
(Answer)