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goldfiish [28.3K]
3 years ago
7

The function f(x) = –x2 – 4x + 5 is shown on the graph. On a coordinate plane, a parabola opens down. It goes through (negative

5, 0), has a vertex at (negative 2, 9), and goes through (1, 0). Which statement about the function is true? The domain of the function is all real numbers less than or equal to −2. The domain of the function is all real numbers less than or equal to 9. The range of the function is all real numbers less than or equal to −2. The range of the function is all real numbers less than or equal to 9.
Mathematics
1 answer:
iragen [17]3 years ago
8 0

Answer:

"The range of the function is all real numbers less than or equal to 9."

Step-by-step explanation:

For this question the domain is (-∞,∞)

The range is all numbers less than 9 (the y-coordinate of the vertex)

The reason the numbers are less than 9 is because the graph is concave down (aka it looks like a frowny face)

Therefore the answer is "The range of the function is all real numbers less than or equal to 9."

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8. Lesly took a test with 30 questions. The ratio of correct answers to incorrect answers
Firlakuza [10]

Lesly got 14 answers correctly.

  • Let the correct answers be C.
  • Let the incorrect answers be I.

<u>Given the following data:</u>

  • Total number of questions = 30 questions.
  • Ratio of C to I = 7 : 8
  • C to I = 7 + 8 = 15

To find the number of answers she got correctly;

C = \frac{7}{15} × 30

C = 7 × 2

<em>Correct answers, C </em><em>= </em><em>14 answers</em>

Therefore, Lesly got 14 answers correctly.

Read more: brainly.com/question/24613908

4 0
3 years ago
How do I solve 2q+10=7q
Lostsunrise [7]
10 is the stubstitution for 5 q, since 2 plus 5 equals 7. What is 10 divided by 5?
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3 years ago
Help me with 16,17,18,and 19 please simpl
mixas84 [53]

Answer:

Ques 16)

We have to simplify the expression:

\dfrac{t^2}{t^2+3t-18}-(\dfrac{5t}{t^2+3t-18}-\dfrac{t-3}{t^2+3t-18})\\   \\=\dfrac{t^2}{t^2+3t-18}-(\dfrac{4t+3}{t^2+3t-18})\\  \\=\dfrac{t^2-4t-3}{t^2+3t+18}

Ques 17)

\dfrac{3w^2+7w-7}{w^2+8w+15}+\dfrac{2w^2-9w+4}{(2w^2+9w-5)(w^2-w-12)}\\  \\=\dfrac{3w^2+7w-7}{w^2+8w+15}+\dfrac{(2w-1)(w-4)}{(2w-1)(w+5)(w+3)(w-4)}\\\\=\dfrac{3w^2+7w-7}{(w+3)(w+5)}+\dfrac{1}{(w+3)(w+5)}\\\\=\dfrac{3w^2+7w-7+1}{(w+3)(w+5)}\\\\=\dfrac{(3w-2)(w+3)}{(w+5)(w+3)}\\\\=\dfrac{3w-2}{w+5}

Ques 18)

Let the blank space be denoted by the quantity 'x'.

\dfrac{x}{12a^2+8a}+\dfrac{15a^2}{12a^2+8a}=\dfrac{7a}{3a+2}\\ \\\dfrac{x+15a^2}{12a^2+8a}=\dfrac{7a}{3a+2}\\\\=\dfrac{x+15a^2}{4a(3a+2)}=\dfrac{7a}{3a+2}\\\\=\dfrac{x+15a^2}{4a}=7a\\\\x+15a^2=28a^2\\\\x=28a^2-15a^2\\\\x=13a^2

Ques 19)

Let the missing quantity be denoted by 'x'.

\dfrac{p^2+7p+2}{p^2+5p-14}-\dfrac{x}{p^2+5p-14}=\dfrac{p-1}{p-2}\\ \\\dfrac{p^2+7p+2-x}{p^2+5p-14}=\dfrac{p-1}{p-2}\\\\\dfrac{p^2+7p+2-x}{(p-2)(p+7)}=\dfrac{p-1}{p-2}\\\\p^2+7p+2-x=(p-1)(p+7)\\\\p^2+7p+2-x=p^2+6p-7\\\\x=p+9


7 0
3 years ago
micheal pays 30 to enter a state fair, plus 4 for each ride. which of the following equations represent his total cost
Shkiper50 [21]

Answer:

I cant see the equation but it should go something along the lines of t = 30 + 4r

Step-by-step explanation:

t = total

r = number of rides

Example: If he went on 4 rides, hen u would imput 4 into r like this

t = 30 + 4 (4)

t = 30 + 16

t = 46

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DochEvi [55]
First day: 25% × 100 = 25 ( miles)
Second day : the remaining distance is 100 - 25 = 75 ( milesl
Third day: 40% × 75 = 30
25 + 75 + 30 = 130 (miles)

5 0
3 years ago
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