24/4=6. 4×6=24.what is the meaning of the unknown factor and quotient?

Audrey ran 2 1/6 miles yesterday. Today, she ran 1 3/6 miles. Tomorrow, she plans on running 1 4/6 miles less than yesterday and

zubka84 [21]

Answer:

2 miles

Step-by-step explanation:

Add the first 2 terms (2 1/6 and 1 3/6) by adding the whole term and fractional term to get 3 4/6, then subtract 1 4/6 by subtracting 1 from 3 and 4/6 from 4/6 to get 2 0/6, which is just 2.

7 0

2 years ago

What is the range of the given function?

topjm [15]

Answer:

-7,-5,-1,0,1,4,6,9

Step-by-step explanation:

6 0

4 years ago

Listed below are the measured radiation absorption rates? (in w/kg) corresponding to 11 cell phones. Use the given data to const

deff fn [24]

Answer:

The minimum value is 0.51

$Q_1= \frac{0.89+1.04}{2}= 0.965$

Median=Q2= 1.18

$Q_3= \frac{1.41+1.42}{2}= 1.415$

Max = 1.49

Step-by-step explanation:

We assume the following dataset:

1.18,1.41, 1.49,1.04,1.04,0.74,0.89,1.42,1.45,0.51,1.38

We order the dataset on increasing way and we have:

0.51 0.74 0.89 1.04 1.04 1.18 1.38 1.41 1.42 1.45 1.49

The minimum value is 0.51

The first quartile Q1 can be calculated with the first 6 observations: 0.51 0.74 0.89 1.04 1.04 1.18. The Q1 would be the average between the 3rd and 4th position:

$Q_1= \frac{0.89+1.04}{2}= 0.965$

For the median since the number of data represent an odd number than the median would be the position in the middle (6th)

Median=Q2= 1.18

The first quartile Q1 can be calculated with the last 6 observations: 1.18 1.38 1.41 1.42 1.45 1.49. The Q1 would be the average between the 3rd and 4th position:

$Q_3= \frac{1.41+1.42}{2}= 1.415$

And the maximum value for this case would be:

Max = 1.49

We can see the boxplot obtained on the figure attached.