The area of this triangle is 958.5 units^2
Let the amount invested with 5% interest be x
Therefore, the amount invested with 6% interest will be (6000-x)
It is given that the total interest earned yearly is $337.5. Thus, the equation of interest will be:
Multiplying both sides by 100 we get:
Subtracting both sides by 36000 we get:
Thus, the amount invested at 5% is $2250
Therefore, the amount invested at 6% will be $(6000-2250)=$3750
Answer:
-1/5
Step-by-step explanation:
#2. (-10, 0) (-10, -8) (0, -8)
#3. (-10, 0) (-10, 8) (-7, 8)
#4. (-10, 0) (-7, 0) (-7, 8)
#8. (0, 8) (0, 0) (8, 0) (10, 4)
#9. (-7, 0) (-7, 8) (0, 8) (0, 0)
#10. (-10, 0) (0, 0) (0, -8)
Not sure about the others. Hope this helps, though.
A) m=months passed
f(m)=2*1.05^m
b) 8 weeks=2 months
f(2)=2*1.05^2=2.205
so essentially still 2
c)100=2*1.05^m
50=1.05^m
log1.05(50)=m
log(50)/log(1.05)=m=80.18
so after 80 months she will have nearly 100 cats (99.12), but will only break through the 100 with her 81st month
