What is the answer to this question?

Mathematics

1 answer:

Leviafan [203]3 years ago

6 0

Answer:

Quadratic: y = -x^2 + 7

Step-by-step explanation:

Diff Diff Diff in

in x x y in y Differences

-2 3

1 -1 6 3

1 0 7 1 -2

1 1 6 -1 -2

1 2 3 -3 -2

The differences in x are all 1. The differences in y are not equal, so it is not linear. The differences in the differences in y are all 2. It is quadratic.

Try: y = -x^2 + 7

x = -2:

y = -(-2)^2 + 7 = -4 + 7 = 3

You get (-2, 3) which is a given point.

Now try the same x value with the other quadratic equation.

y = x^2 + 7

x = -2:

y = (-2)^2 + 7 = 4 + 7 = 11

You get (-2, 11) which is not a given point.

Answer:

Quadratic: y = -x^2 + 7

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Reika [66]

Answer:

$-\frac{1}{2} \vec {c}$

Step-by-step explanation:

Look at the component form of each vector.

Note that vector c is <4,4> and vector d is <-2,-2>

If one imagined the line that contained each vector, the line for both would have a slope of 1, because $\frac{4}{4}=1=\frac{-2}{-2}$

Since they have the same slope they are parallel, but since they are in opposite directions, we often call them "anti-parallel" (simply meaning parallel, but in opposite directions).

If two vectors are parallel, one vector can be multiplied by a scalar to result in the other vector. This means that there is some number "k", such that $k \vec{c} = \vec {d}$ , or equivalently, $kc_x=d_x$ and $kc_y=d_y$ .