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Paul [167]
3 years ago
13

What is the minimum value of the objective function, C with given constraints? C=5x+3y {⎨x+3y≤9 {5x+2y≤20 {x≥1 {y≥2

Mathematics
1 answer:
Solnce55 [7]3 years ago
3 0

Answer:

The answer is below

Step-by-step explanation:

Plotting the following constraints using the online geogebra graphing tool:

x + 3y ≤ 9         (1)

5x + 2y ≤ 20    (2)

x≥1 and y≥2      (3)

From the graph plot, the solution to the constraint is A(1, 2), B(1, 2.67) and C(3, 2).

We need to minimize the objective function C = 5x + 3y. Therefore:

At point A(1, 2): C = 5(1) + 3(2) = 11

At point B(1, 2.67): C = 5(1) + 3(2.67) = 13

At point C(3, 2): C = 5(3) + 3(2) = 21

Therefore the minimum value of the objective function C = 5x + 3y is at point A(1, 2) which gives a minimum value of 11.

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Korvikt [17]

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8 0
3 years ago
Danielle earns a 7.25% commission on everything she sells at the electronics store where she works. She also earns a base salary
Nikitich [7]

Answer:

Last week her sales were <u>$4500</u>.

Step-by-step explanation:

Given:

Danielle earns a 7.25% commission on everything she sells at the electronics store where she works.

She also earns a base salary of $750 per week.

Her total earnings for the week were $1,076.25.

Now, to find her sales last week.

Let the sales of last week be x.

Base salary = $750.

Total earnings = $1076.25.

So, we deduct the base salary from the total earnings first:

1076.25-750

=326.25.

Thus, the rest of the earnings is $326.25 which is the 7.25% commission on sales.

Now, to get the sales of last week we put an equation:

7.25\%\ of\ x=326.25

\frac{7.25}{100} \times x=326.25

\frac{7.25x}{100} =326.25

<em>Multiplying both sides by 100 we get:</em>

7.25x=32625

<em>Dividing both sides by 7.25 we get:</em>

x=4500.

The sales of last week = $4500.

Therefore, last week her sales were $4500.

7 0
3 years ago
-[x-2]=x+2 please help
ELEN [110]
-(x-2) = x + 2
- x + 2 = x + 2
2x = 0
x = 0

i am a mathematics teacher. if anything to ask please pm me
5 0
3 years ago
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