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Paul [167]
3 years ago
13

What is the minimum value of the objective function, C with given constraints? C=5x+3y {⎨x+3y≤9 {5x+2y≤20 {x≥1 {y≥2

Mathematics
1 answer:
Solnce55 [7]3 years ago
3 0

Answer:

The answer is below

Step-by-step explanation:

Plotting the following constraints using the online geogebra graphing tool:

x + 3y ≤ 9         (1)

5x + 2y ≤ 20    (2)

x≥1 and y≥2      (3)

From the graph plot, the solution to the constraint is A(1, 2), B(1, 2.67) and C(3, 2).

We need to minimize the objective function C = 5x + 3y. Therefore:

At point A(1, 2): C = 5(1) + 3(2) = 11

At point B(1, 2.67): C = 5(1) + 3(2.67) = 13

At point C(3, 2): C = 5(3) + 3(2) = 21

Therefore the minimum value of the objective function C = 5x + 3y is at point A(1, 2) which gives a minimum value of 11.

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This means there are (15-7) 8 sad clowns.

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6 0
3 years ago
I need the steps to this, please. It says solve for x. Each figure is a parallelogram. Show your work.
Trava [24]
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FH is one diagonal that is split into two equal pieces by the other diagonal EG.

The two parts of FH (KH and KF) are congruent to each other, so KH = KF. They combine back to FH


By the segment addition postulate
KH + KF = FH
KH + KH = FH .... KF has been replaced with KH (works because KF = KH)
2*KH = FH

Now use substitution
2*KH = FH
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----------------------------------------
----------------------------------------

Answer: x = 8

5 0
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