What is the minimum value of the objective function, C with given constraints? C=5x+3y {⎨x+3y≤9 {5x+2y≤20 {x≥1 {y≥2
1 answer:
Answer:
The answer is below
Step-by-step explanation:
Plotting the following constraints using the online geogebra graphing tool:
x + 3y ≤ 9 (1)
5x + 2y ≤ 20 (2)
x≥1 and y≥2 (3)
From the graph plot, the solution to the constraint is A(1, 2), B(1, 2.67) and C(3, 2).
We need to minimize the objective function C = 5x + 3y. Therefore:
At point A(1, 2): C = 5(1) + 3(2) = 11
At point B(1, 2.67): C = 5(1) + 3(2.67) = 13
At point C(3, 2): C = 5(3) + 3(2) = 21
Therefore the minimum value of the objective function C = 5x + 3y is at point A(1, 2) which gives a minimum value of 11.
You might be interested in
Step-by-step explanation:
Recall that 1 dozen = 12 so 4 dozen cookies has a total of 48 cookies. We are going to use the following ratios to solve the problem:
and
a)
b) 18 dozen cookies = 216 cookies
Answer:
x ≥ - 2.
Step-by-step explanation:
We have to solve the compound inequality.
It is 15 ≥ - 3x or x ≥ - 2
Now, from the first part we have
15 ≥ -3x
⇒
⇒ - 5 ≤ x
⇒ x ≥ - 5 ....... (1)
And the second part is x ≥ -2 ......... (2)
Therefore, the conditions (1) and (2) will both be true if x ≥ - 2.
Hence, this is the solution. (Answer)