Hello : let A(6,-1) B(-3,-1)<span>
the slope is : (YB - YA)/(XB -XA)
(-1+1)/(-3+6) = 0
the slope is : 0 ...(answer : </span>B.) 0 )
B I’m pretty sure okay bye
Answer:
(x×11)÷52.25
Step-by-step explanation:
if 11=52.25 and y=x then x11÷52.25 i think that is the answer
Answer:
![f^{-1}(x)=\sqrt[3]{x}-1](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D-1)
Step-by-step explanation:
![f(x)=(x+1)^3\\\\y=(x+1)^3\\\\x=(y+1)^3\\\\\sqrt[3]{x}=y+1\\\\y=\sqrt[3]{x}-1\\ \\f^{-1}(x)=\sqrt[3]{x}-1](https://tex.z-dn.net/?f=f%28x%29%3D%28x%2B1%29%5E3%5C%5C%5C%5Cy%3D%28x%2B1%29%5E3%5C%5C%5C%5Cx%3D%28y%2B1%29%5E3%5C%5C%5C%5C%5Csqrt%5B3%5D%7Bx%7D%3Dy%2B1%5C%5C%5C%5Cy%3D%5Csqrt%5B3%5D%7Bx%7D-1%5C%5C%20%5C%5Cf%5E%7B-1%7D%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D-1)
Graphing both inverses, they will be symmetrical about the line 
.
The angle between two vectors is:
CosФ = u - v / Magnitude(u) x magnitude(v)
Magnitude of u = SQRT(7^2 + -2^2) = SQRT(49 +4) = SQRT(53)
Magnitude of v = SQRT(-1^2 +2^2) = SQRT(1 +4) = SQRT(5)
u x v = (7 x -1) + (-2 x 2) = -7 + -4 = -11
cosФ = -11 / sqrt(53) x sqrt(5)
cosФ = -11sqrt265) / 265
Ф =cos^-1(-11sqrt265) / 265)
Ф=132.51 degrees.
