Answer:
<u><em>x = 4</em></u>
<u><em>x = 3</em></u>
<em><u>x = 10</u></em>
<u><em>x = 3</em></u>
<em><u>x = 16</u></em>
<em><u>x = 35</u></em>
Step-by-step explanation:

x · 10 = 5 · 8
10x = 40
10x ÷ 10 = 40 ÷ 10
<u><em>x = 4</em></u>

x · 8 = 12 · 2
8x = 24
8x ÷ 8 = 24 ÷ 8
<u><em>x = 3</em></u>

x · 3 = 15 · 2
3x = 30
3x ÷ 3 = 30 ÷ 3
<em><u>x = 10</u></em>

x · 12 = 6 · 6
12x = 36
12x ÷ 12 = 36 ÷ 12
<u><em>x = 3</em></u>

x · 2 = 8 · 4
2x = 32
2x ÷ 2 = 32 ÷ 2
<em><u>x = 16</u></em>

x · 2 = 10 · 7
2x = 70
2x ÷ 2 = 70 ÷ 2
<em><u>x = 35</u></em>
The answer is 0.60 because the sum of the shaded angles equals 145°, divided by 360° equals 0.60
Find the volume of each tank by multiplying the length by the width by the height:
Terry: 14 x 12 x 10 = 1680 cubic cm.
Bob: 13 x 15 x 8 = 1560 cubic cm
Terry’s aquarium is larger and can hold more water.
Answer:
Both fireworks will explode after 1 seconds after firework b launches.
Step-by-step explanation:
Given:
Speed of fire work A= 300 ft/s
Speed of Firework B=240 ft/s
Time before which fire work b is launched =0.25s
To Find:
How many seconds after firework b launches will both fireworks explode=?
Solution:
Let t be the time(seconds) after which both the fireworks explode.
By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation
Firework A= 330(t)
Firework B=240(t)+240(0.25)
Since we need to know the same time after which they explode, we can equate both the equations
330(t) = 240(t)+240(0.25)
300(t)= 240(t)+60
300(t)-240(t)= 60
60(t)=60

t=1