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2 years ago

2+2 ..................................needed 20 characters

2 answers:

8 0

2+2 equals 4 the answer is 4 because if you two groups of apple and in each group there are two apples so in all their are 4 apples

Sloan [31]2 years ago

7 0

Answer:

plese mark me brainlist

Step-by-step explanation:

thankyou and have nice day

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Divide these polynomial a (27x 4 - 18x 3 + 9x 2) ÷ 3x

Blizzard [7]

The answer is 9x^3-6x^2+3x

5 0

2 years ago

Prove that 3:8 is equivalent to 12:32

Andrei [34K]

3*4=12
8*4=32
It is a ratio.

6 0

3 years ago

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John has $220 in his account and adds $25 to it each month. Cheryl has $100 in her account and adds $35 each month to her accoun

Morgarella [4.7K]

Answer:

$695

Step-by-step explanation:

6 0

2 years ago

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Number 2 I need help on how to solve it

Hunter-Best [27]

Let's simplify the following expression:

$\text{ }\frac{\text{ \lparen2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{\text{ 6x}^5\text{y}^{-4}\text{z}^{-5}}{\text{ \lparen2x}^6\text{y}^3\text{z}^{-3})^2}$

We get,

$\text{ }\frac{(\text{2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{6x^5y^{-4}z^{-5}}{(2x^6y^3z^{-3})^2}$ $\text{ }\frac{(2x^4-y^6z^{-4})^2(6x^5y^{-4}z^{-5})}{(2x^2z^3)(2x^6y^3z^{-3})^2}$ $\text{ }\frac{(4x^8\text{ - 4x}^4y^6z^{-4}\text{ + y}^{12}z^{-8})(6x^5y^{-4}z^{-5})}{(2x^2z^3)(4x^{12}y^6z^{-6})}$ $\text{ }\frac{24x^{13}y^{-4}z^{-5}\text{ - 24x}^9y^2z^{-9}\text{ + 6x}^5y^8z^{-13}}{8x^{14}y^6z^{-3}}$

4 0

9 months ago

Determine the greatest common divisor of the elements of the set \[ s = \{ n^{13} - n \mid n \in \mathbb{z} \}. \]

Kay [80]

Answer:

2730

Step-by-step explanation:

We want to determine the greatest common divisor of the elements of the set $S = \{ n^{13} - n \mid n \in \mathbb{Z} \}.$

We apply the Fermat's little theorem which states that if p is a prime number, then for any integer a, the number aᵖ − a is an integer multiple of p.

Now, $n^{13} \equiv n \mod p$ if p-1 divides 12.

Since the of 12 are 1,2,3,4, 6, 12, the corresponding primes are 2, 3, 5, 7, 13.

Therefore, the gcd of the elements in $2^{13}-2$ and $3^{13}-3$ is 2 \cdot 3 \cdot 5 \cdot 7 \cdot 13.$

2*3*5*7*13=2730

Therefore, the gcd of the elements in set S is 2730.

5 0

2 years ago