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Maksim231197 [3]
3 years ago
12

What is the slope of the linear function given the following table?

Mathematics
1 answer:
alukav5142 [94]3 years ago
5 0

Answer:

Well since this question is asking for a slope I got -2/3. Correct me if I am wrong

Step-by-step explanation:

I use (0,4) and (3,2)

I use the slope formula

y2-y1/x2-x1

2-4/3-0=-2/3

I got -2/3

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Easy math question Help this is due today
Natasha2012 [34]

Answer:

Use the pythagorean theorem to solve.

Step-by-step explanation:

2^{2}+3^{2}=c^2\\4+9=c^2\\13=c^2\\\\\\sqrt{13} =\sqrt{c^2}

The square root and the square cancel out. Then your answer will be the square root of 13 or 3.60555127546. Since the instructions say to round to 2 places we will do so. 3.61 meters is the length of the slide

7 0
3 years ago
P=−4b 2 +6b−9 <br> Q=7b 2 −2b−5<br> ​P−Q=<br> Your answer should be a polynomial in standard form.
shepuryov [24]

Answer:

−11b^2+8b−4

Step-by-step explanation:

−4b2+6b−9−7b2+2b+5

Simplify by adding terms.

11b2+8b−4

3 0
3 years ago
Find P(x)=... polynomial
Aneli [31]

Answer: D) P(x) = -23

Step-by-step explanation:

Substitute 2 for x:

1 - 2(2)^2-3(2)^2+4(2)

Exponent

1-2(4)-3(8)+4(2)

Multiply

1-8-24+8

Combine like terms

-23

<em>Hope it helps <3</em>

3 0
3 years ago
A suvery shows that 55℅​
gizmo_the_mogwai [7]

Answer: No. The intervals defined by the margin or error overlap

Step-by-step explanation:

If we think about it, with the worst margins, 55% could be 48% and then the 45% would be 52%, showing there is no clear yes or no and it is possible that the intervals could overlap

7 0
2 years ago
Write an equation of the line that passes through (1,2) and is parallel to the line y=-5x+4
valentinak56 [21]

Answer:

The equation of the Parallel line to the given line is  5x+y-7=0

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given that the line y = - 5x+4 and point (1,2)

The equation of the Parallel line to the given line is  ax+by+k=0

Given straight line  5x + y -4 =0

The equation of the Parallel line to the given line is  5x+y+k=0

This line passes through the point (1,2)

             5x+y+k=0

            5(1)+2+k=0

⇒              7+k=0

                   k =-7

<u>Final answer:-</u>

The equation of the Parallel line to the given line is  5x+y-7=0

7 0
3 years ago
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