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Wittaler [7]
2 years ago
14

Uma empresa de taxi cobra a bandeira de 5,00 ainda o valor de 1,50 para cada quilometro rodado determine a lei da funçâo corresp

odente ao valor cobrado pelos taxis dessa empresa
Mathematics
1 answer:
weqwewe [10]2 years ago
7 0

Answer:

y = 5 + 1.5x

Step-by-step explanation:

The law of function would be shown below:

Let us assume that the amount charged by the taxis of this company is equivalent to y.

And, x is the amount of kilometers traveled.

So as per the given statement, the taxi charged $5 plus $1.50 per km

Therefore the law of function would be

y = 5 + 1.5x.

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you would now have 22 homework problems

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Danielle put 4.902 gallons of gasoline in a gas tank. What is 4.902 written in expanded form?
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6 0
2 years ago
What is the approximate result of converting 20 centimeters into inches? remember that 1inch = 2.54centimeters
marta [7]
20 cm * 1 inch / 2.54 cm = <span> <span> <span> 7.874015748 </span> </span> </span> inches
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6 0
3 years ago
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A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall
Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : \mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7

Standard deviation : \sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}

=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}

=\dfrac{30.265}{10}=3.0265

The confidence interval for the population mean (for sample size <30) is given by :-

\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}

Given significance level : \alpha=1-0.95=0.05

Critical value : t_{n-1,\alpha/2}=t_{9,0.025}=2.262

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)

Hence, 95% confidence interval for the true mean= (2.54,6.86)

7 0
3 years ago
A castle is surrounded by a circular moat which is 5 m wide
Elanso [62]

Answer:

  1414 kL

Step-by-step explanation:

The volume of the donut-shaped moat is the product of its surface area and depth. The area is the product of its centerline length and its width.

<h3>Moat area</h3>

The diameter of the centerline of the moat is (50 m -5 m) = 45 m. The length of that centerline is ...

  C = πd = π(45 m) = 45π m

The area is this length times the width of the moat:

  moat area = (45π m)(5 m) = 225π m²

<h3>Moat volume</h3>

The volume is the product of the area and the depth of the moat:

  V = Ah = (225π m²)(2 m) = 450π m³ ≈ 1413.72 m³

1 cubic meter is 1000 liters, 1 kiloliter.

The volume of the moat is about 1414 kL.

5 0
1 year ago
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