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2 years ago

ANSWER ASAP PLEASE. I WILL GIVE BRAINLIEST IF YOU'RE CORRECT <3 TY

Mathematics

2 answers:

xenn [34]2 years ago

4 0

Answer:

Answer is = A

Step-by-step explanation:

Just did the A-P-E-x

andreyandreev [35.5K]2 years ago

3 0

Answer:

Step-by-step explanation:

A, B and D are all false based on the data. C is true

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Verify cot x sec^4x=cotx +2tanx +tan^3x

Tanzania [10]

Answer:

See explanation

Step-by-step explanation:

We want to verify that:

$\cot(x) \: { \sec}^{4} x = \cot(x) + 2 \tan(x) + { \tan}^{3} x$

Verifying from left, we have

$\cot(x) \: { \sec}^{4} x = \cot(x) \: ( 1 + { \tan}^{2} x )^{2}$

Expand the perfect square in the right:

$\cot(x) \: { \sec}^{4} x = \cot(x) \: ( 1 + { 2\tan}^{2} x + { \tan}^{4} x)$

We expand to get:

$\cot(x) \: { \sec}^{4} x = \cot(x) \: + \cot(x){ 2\tan}^{2} x +\cot(x) { \tan}^{4} x$

We simplify to get:

$\cot(x) \: { \sec}^{4} x = \cot(x) \: + 2 \frac{ \cos(x) }{\sin(x) ) } \times \frac{{ \sin}^{2} x}{{ \cos}^{2} x} +\frac{ \cos(x) }{\sin(x) ) } \times \frac{{ \sin}^{4} x}{{ \cos}^{4} x}$

Cancel common factors:

$\cot(x) \: { \sec}^{4} x = \cot(x) \: + 2 \frac{{ \sin}x}{{ \cos}x} +\frac{{ \sin}^{3} x}{{ \cos}^{3} x}$

This finally gives:

$\cot(x) \: { \sec}^{4} x = \cot(x) + 2 \tan(x) + { \tan}^{3} x$

3 0

2 years ago

How do you solve -3x+d=-9

zhuklara [117]

Step 1: Add 3x to both sides.d−3x+3x=−9+3xd=3x−9 = ANSWER

Can you possibly help me on my recent question?

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2 years ago

16 increased by twice a number is -24

wlad13 [49]

X-the number

16 + 2x = -24 |subtract 16 from both sides

2x = -40 |divide both sides by 2

<u>x = -20</u>

Answer: <em>The number is -24</em>

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2 years ago

Which of the following addition problems yields a sum that is an irrational number? Select TWO that apply. 23+97 2√+2√ 32+25√ 4√

GuDViN [60]

Answer:

28n 72uwbs jsjsbkajskld

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2 years ago

Which inequalities can be used to find the solution set of the following inequality? Check all that apply.

VikaD [51]

Answer: its A and D

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2 years ago

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