All categories

3 years ago

ANSWER ASAP PLEASE. I WILL GIVE BRAINLIEST IF YOU'RE CORRECT <3 TY

Mathematics

2 answers:

xenn [34]3 years ago

4 0

Answer:

Answer is = A

Step-by-step explanation:

Just did the A-P-E-x

andreyandreev [35.5K]3 years ago

3 0

Answer:

Step-by-step explanation:

A, B and D are all false based on the data. C is true

You might be interested in

Five coats cost for pound how much to 7 cakes cost

Elanso [62]

1 pound and 2/7 hoped this helped

5 0

3 years ago

A survey of 100 people asked if they have a dog or a cat. The answers were: 56 people answered yes for dog and 51 people answere

den301095 [7]

Answer: The maximum number of people who could answer yes for both cat and dog is 7.

Step-by-step explanation: Given that a survey of 100 people asked if they have a dog or a cat.

Out of those 100 people, 56 people answered yes for dog and 51 people answered yes for cat. Some people may own neither and some people may own both animals.

We are to find the maximum number of people that could answer yes for both cat and dog.

Let A and B represents the set of people that answered Yes for dog and Yes for cat respectively.

Then, according to the given information, we have

$n(A)=56,~~n(B)=51.$

From Set Theory, we have

$n(A\cup B)=n(A)+n(B)-n(A\cap B)\\\\\Rightarrow n(A\cup B)=56+51-n(A\cap B)\\\\\Rightarrow n(A\cup B)=107-n(A\cap B)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Since the total number of people is 100, so we get

$n(A\cup B)\geq 100.$

Therefore, from equation (i), we get

$107-n(A\cap B)\geq 100\\\\\Rightarrow n(A\cap B)\leq 107-100\\\\\Rightarrow n(A\cap B)\leq 7.$

Thus, the maximum number of people who could answer yes for both cat and dog is 7.

4 0

3 years ago

Read 2 more answers

5x -4(x - 3) - 8 = Ax + B

Brrunno [24]

Answer:

12= ax - x + b

Step-by-step explanation:

5x -4(x - 3) - 8 = ax + b

5x -4x + 12 - 8 = ax + b

x + 12 = ax + b

12= ax - x + b

4 0

3 years ago

Á size 8 kids shoe measures 9 2/3 inches. if 5 pairs of size 8 shoes are lined end to end, then how many inches will they cover?

castortr0y [4]

5 pairs of shoes = 10 shoes

$9\frac{2}{3} \times (5 \times 2) \\ \\ = 9 \dfrac{2}{3} \times 10 \\ \\ = 96\dfrac{2}{3}$

They will cover 96 2/3 inches.

Hope this helps. - M

6 0

4 years ago

Find the exact value of the expression.<br> tan( sin−1 (2/3)− cos−1(1/7))

Sonja [21]

Answer:

$\tan(a-b)=\frac{2\sqrt{5}-20\sqrt{3}}{5+8\sqrt{15}}$

Step-by-step explanation:

I'm going to use the following identity to help with the difference inside the tangent function there:

$\tan(a-b)=\frac{\tan(a)-\tan(b)}{1+\tan(a)\tan(b)}$

Let $a=\sin^{-1}(\frac{2}{3})$ .

With some restriction on $a$ this means:

$\sin(a)=\frac{2}{3}$

We need to find $\tan(a)$ .

$\sin^2(a)+\cos^2(a)=1$ is a Pythagorean Identity I will use to find the cosine value and then I will use that the tangent function is the ratio of sine to cosine.

$(\frac{2}{3})^2+\cos^2(a)=1$

$\frac{4}{9}+\cos^2(a)=1$

Subtract 4/9 on both sides:

$\cos^2(a)=\frac{5}{9}$

Take the square root of both sides:

$\cos(a)=\pm \sqrt{\frac{5}{9}}$

$\cos(a)=\pm \frac{\sqrt{5}}{3}$

The cosine value is positive because $a$ is a number between $-\frac{\pi}{2}$ and $\frac{\pi}{2}$ because that is the restriction on sine inverse.

So we have $\cos(a)=\frac{\sqrt{5}}{3}$ .

This means that $\tan(a)=\frac{\frac{2}{3}}{\frac{\sqrt{5}}{3}}$ .

Multiplying numerator and denominator by 3 gives us:

$\tan(a)=\frac{2}{\sqrt{5}}$

Rationalizing the denominator by multiplying top and bottom by square root of 5 gives us:

$\tan(a)=\frac{2\sqrt{5}}{5}$

Let's continue on to letting $b=\cos^{-1}(\frac{1}{7})$ .

Let's go ahead and say what the restrictions on $b$ are.

$b$ is a number in between 0 and $\pi$ .

So anyways $b=\cos^{-1}(\frac{1}{7})$ implies $\cos(b)=\frac{1}{7}$ .

Let's use the Pythagorean Identity again I mentioned from before to find the sine value of $b$ .

$\cos^2(b)+\sin^2(b)=1$

$(\frac{1}{7})^2+\sin^2(b)=1$

$\frac{1}{49}+\sin^2(b)=1$

Subtract 1/49 on both sides:

$\sin^2(b)=\frac{48}{49}$

Take the square root of both sides:

$\sin(b)=\pm \sqrt{\frac{48}{49}$

$\sin(b)=\pm \frac{\sqrt{48}}{7}$

$\sin(b)=\pm \frac{\sqrt{16}\sqrt{3}}{7}$

$\sin(b)=\pm \frac{4\sqrt{3}}{7}$

So since $b$ is a number between $0$ and $\pi$ , then sine of this value is positive.

This implies:

$\sin(b)=\frac{4\sqrt{3}}{7}$

So $\tan(b)=\frac{\sin(b)}{\cos(b)}=\frac{\frac{4\sqrt{3}}{7}}{\frac{1}{7}}$ .

Multiplying both top and bottom by 7 gives:

$\frac{4\sqrt{3}}{1}= 4\sqrt{3}$ .

Let's put everything back into the first mentioned identity.

$\tan(a-b)=\frac{\tan(a)-\tan(b)}{1+\tan(a)\tan(b)}$

$\tan(a-b)=\frac{\frac{2\sqrt{5}}{5}-4\sqrt{3}}{1+\frac{2\sqrt{5}}{5}\cdot 4\sqrt{3}}$

Let's clear the mini-fractions by multiply top and bottom by the least common multiple of the denominators of these mini-fractions. That is, we are multiplying top and bottom by 5:

$\tan(a-b)=\frac{2 \sqrt{5}-20\sqrt{3}}{5+2\sqrt{5}\cdot 4\sqrt{3}}$

$\tan(a-b)=\frac{2\sqrt{5}-20\sqrt{3}}{5+8\sqrt{15}}$

4 0

3 years ago