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swat32
3 years ago
15

ANSWER ASAP PLEASE. I WILL GIVE BRAINLIEST IF YOU'RE CORRECT <3 TY

Mathematics
2 answers:
xenn [34]3 years ago
4 0

Answer:

Answer is = A

Step-by-step explanation:

Just did the A-P-E-x

andreyandreev [35.5K]3 years ago
3 0

Answer:

C

Step-by-step explanation:

A, B and D are all false based on the data. C is true

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Find the midpoint between the two points (-7, -2) and (-7,2).<br><br>answer (?,?) <br><br>plz help​
olga_2 [115]

Answer:

(-7,0)

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Or the figure shown on the​ right, find m∠3 and m∠4.
ioda

Answer:

m<3=84

m<4=96

Step-by-step explanation:

180-43-41=96

180-96=84

4 0
3 years ago
Read 2 more answers
find x if the distance between points L and M is 15 and point M is located in the first quadrant. L=(-6,2) M=(x,2)​
aivan3 [116]

Answer:

Therefore,

x = 9

Step-by-step explanation:

Given:

Let,  

point L( x₁ , y₁) ≡ ( -6 , 2)

point M( x₂ , y₂ )≡ (x , 2)

l(AB) = 15 units  (distance between points L and M)

To Find:    

x = ?

Solution:  

Distance formula between Two points is given as

l(LM)^{2} = (x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}

Substituting the values we get

15^{2}=(x--6)^{2}+(2-2)^{2}\\\\225=(x+6)^{2}

Square Rooting we get

(x+6)=\pm \sqrt{225}=\pm 15\\\\x+6 = 15\ or\ x+6 = -15\\\\x= 9\ or\ x = -21

As  point M is located in the first quadrant

x coordinate and y coordinate are positive

So x = -21 DISCARDED

Hence,

x = 9

Therefore,

x = 9

3 0
3 years ago
(Hehe...Please ignore the markings)
inysia [295]

Answer:

See below:

Step-by-step explanation:

Problem 1:

Multiply Equation 1 by 4, keep Equation 2 the same.

x+y=8, multiply each term by 4:

4*x=4x, 4*y=4y, 8*4=32

so, the equivalent system is: 4x+4y=32 and x-y=2

Solve the system of equations:

x-y=2 becomes x=y+2

plug into 4x+4y=32 to solve for y

4(y+2)+4y=32---> 4y+8+4y=32--->8y=24---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 1 Answer:

Equivalent system: 4x+4y=32, x-y=2; solution: x=5, y=3

Problem 2:

Keep Equation 1 the same. Add 1 and 2.

To add an equation, add the left sides together, and then the rights.

so: x+y=8 + x-y=2 gives us: 2x=10

solve for x ---> 2x/2=10/2--->x=5

plug x into x+y=8--->5+y=8--->y=3

Problem 2 answer:

Equivalent system: x+y=8, 2x=10; solution:x=5, y=3

Problem 3:

Subtract Equation 2 from 1, and keep 2 the same.

To subtract an equation, subtract the left sides, then the rights. We are subtracting 1<em> from </em>2, so its 2-1.

x-y=2 - x+y=8 gives us: -2y=-6

Solve for y by dividing by -2-->-2y/-2=-6/-2---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 3 answer:

Equivalent system: -2y=-6, x-y=2; solution: x=5, y=3

Problem 4:

Multiply the sum of Equation 1 and 2 by a factor of 3. Keep equation 2 the same.

First we add 1 and 2: (we did this earlier) ---> 2x=10 ---> now we multiply it all by 3---> 2x*(3)=10*(3)---> this gives us: 6x=30---> now divide by 6 to solve for x: 6x/6=30/6 gives us: x=5

Now, solve for y by plugging x into equation 2: x-y=2---> 5-y=2--->y=3

Problem 4 answer:

Equivalent system: 6x=30, x-y=2; solution: x=5, y=3

______

Quick Tip: One thing inherent of Equivalent systems is that they have the same set of solutions. Thus, we know the systems are equivalent when they have the same set of solutions for x and y. Moreover, you don't need to solve every time after you attempt to find an equivalent system, instead, just plug in the values found in problem 1 to each new set of equations to test if they are equivalent.

If we find x=5 and y=3 for x+y=8 and x-y=2, then all we have to do is plug them in to 6x=30 and -2y=-6 to see if they are equivalent.

6(5)=30 ---> true

-2(3)=-6 ---> true

3 0
3 years ago
64-144a+108a^2-27a^3​
solmaris [256]

the answer for this question is 64-144a+108a^2-27a^3

3 0
3 years ago
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