2to 5th power times 5
2 answers:
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Answer:
Step-by-step explanation:
Given that:
10 number of blocks which have numbers from 1 through 10.
To find:
Probability of randomly choosing a block that has an even number.
Solution:
The given set of numbers is: {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
There are a total of 5 Even numbers are {2, 4, 6, 8, 10}.
And There are a total of 5 Odd number are {1, 3, 5, 7, 9}.
Formula for probability of an event <em>E</em> can be observed as:
Here, Event <em>E </em>is randomly choosing an even number.
Number of favorable cases = 5
Total number of cases = 10
Therefore, the required probability is:
1.) c. x^2−2x+4−14/x+2
2.) The remainder is 1/2x-1. When you divide 8x^2+4x−3 by 2x-1, your answer is 4x+4 remainder 1/2x-1.
3.)The remainder is 6/(x+3) because when you divide 7x^2+15x−12 by x+3, you get 7x-6 remainder 6/x+3
The work is attached if you need it, sorry for the messiness!
