What is the measure of angle RSL if it is (9x+27)° and angle BSA is (6x+66)°
2 answers:
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Answer:
The distance of helicopter from the injured person is 542.82 feet
Step-by-step explanation:
Given as :
The height of the hovering helicopter above the ground = h = 450 feet
The angle of elevation from injured person to helicopter = Ф = 56°
Or, Let the distance of of helicopter from person = x feet
Now, From Triangle
∵ Sin Ф =
∴ Sin 56° =
Or, 0.8290 =
Or , x =
I.e x = 542.82 feet
So, The distance from injured person to helicopter = 542.82 feet
Hence The distance of helicopter from the injured person is 542.82 feet Answer