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3 years ago

Find the volume of the rectangular prism , in cubic centimeters please answer

Mathematics

1 answer:

12345 [234]3 years ago

8 0

Answer:

the volume of the rectangular prism = 166.336 cubic cm

Hence, option C is correct.

Step-by-step explanation:

We can determine the volume of the rectangular prism using the formula given below.

The volume of the rectangular prism = Base area x Height

Determining the Base area:

Given

Length l = 3.2 cm

Width w = 4.6 cm

Area of the Base area = l × w

= 3.2 × 4.6

= 14.72 cm²

Thus, the area of the Base area = 14.72 cm²

As the height h = 11.3 cm

Thus,

The volume of the rectangular prism = Base area x Height

= 14.72 x 11.3

= 166.336 cubic cm

Therefore, the volume of the rectangular prism = 166.336 cubic cm

Hence, option C is correct.

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The question does not seem complete, but I'll represent the statement mathematically and look for their ages each. This is because the worst they can ask for is their ages.

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C = 2A

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3 years ago

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3 years ago

Find the length and width of a rectangle that has the given area and a minimum perimeter. Area: 162 square feet

Gnom [1K]

Answer:

The width and length of rectangle is 12.728 m

Step-by-step explanation:

Let the length of the rectangle = L

let the width of the rectangle = W

The subjective function is given by;

F(p) = 2(L + W)

F = 2L + 2W

Area of the rectangle is given by;

A = LW

LW = 162 ft²

L = 162 / W

Substitute in the value of L into subjective function;

$f = 2l + 2w\\\\f = 2(\frac{162}{w} )+2w\\\\f = \frac{324}{w} + 2w\\\\\frac{df}{dw} = \frac{-324}{w^2} +2\\\\$

Take the second derivative of the function, to check if it will given a minimum perimeter

$\frac{d^2f}{dw^2}= \frac{648}{w^3} \\\\Thus, \frac{d^2f}{dw^2}>0, \ since,\frac{648}{w^3} >0 \ (minimum \ function \ verified)$

Determine the critical points of the first derivative;

df/dw = 0

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L = 162 / 12.728

L = 12.728 m

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3 0

3 years ago

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Lina20 [59]

Answer:

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Step-by-step explanation:

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Since the equation has x-values, you would give the first number (x-coordinate) as your answer.

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