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chubhunter [2.5K]
3 years ago
6

Question 1 (0.5 points)

Mathematics
1 answer:
Finger [1]3 years ago
8 0

Answer:

39.91 degrees.

Step-by-step explanation:

Formula

Sin(A)/a = Sin(B) / b

Givens

  • A = 84
  • a = 31
  • B = ?
  • b = 20

Solution

Sin(84)/31 = Sin(B)/20

20*Sin(84) / 31 = Sin(B)

Sin(B) = 0.6416

B = 39.91 degrees.

====================

This looks like it is right, but you should check. Let h be the height opposite angle A.

h/20 = sin(39.91)

h = 20*sin(39.91)

h = 12.83

31 has to be longer than that amount (which it is.) So there is one solution.

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PilotLPTM [1.2K]
The correct answer is B. x is greater than -2.

7 0
3 years ago
I need to write an algebraic expression that includes 2 constatants, 2 variables, and 2 different operations. It also need it in
belka [17]

Answer:

An example would be

(x+3)-(y+12)

The two constants are 3 and 12 (I'm assuming you meant "constant" as in the number that stands by itself and not "constatant" lol)

The two variables are x and y

The two operations are addition and subtraction

In words you could say "the quantity of x plus three minus the quantity of y plus twelve"

3 0
3 years ago
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Len [333]

Answer:

42300000

Step-by-step explanation:

Use known fact

1\ km=1000\ m

Consider 1 square kilometer:

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So, to find the answer, you have to multiply given number of square kilometers by 1000000:

42.3\ km^2=42.3\times 1000000\ m^2=42300000\ m^2

4 0
3 years ago
$12,000 is invested for 4 years at a simple interest rate of 1.5%. How much does the investment earn?
bixtya [17]
12'000×1.5 I think might need to multiple your answer by 4 yet
5 0
3 years ago
Which ordered pair makes both inequalities true?
kvasek [131]

Answer:

(3, 0)

Step-by-step explanation:

Given the inequality y > -2x + 3 and y ≤ x - 2

The graph of the inequalities are plotted using the geogebra graphing online calculator.

The portion of the graph that is shaded with dark blue, represents the portion that supports the equation.

All the ordered pair points given in the question are also labelled in the graph.

From the graph we can see that only point (3, 0) falls in the area that supports the equation. Hence (3, 0) makes both inequalities true.

6 0
3 years ago
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