Answer:
i so exponets are numbers that can go into anything
Step-by-step explanation:
i just told you
Let's think about the information in the problem. The problem tells us a few key points:
- The number of rabbits grows exponentially
- We start with 20 rabbits (
, 
) - After 6 months (
), we have 100 rabbits (
)
Since we know we are going to be working with an exponential model, we can start with a base exponential model:
is the principal, or starting amount
is the growth/decay rate (in this case, growth)
is the number of months
is the number of rabbits
Based on the information in the problem, we can create two equations:
The first equation tells us that 
, or that we start with 20 rabbits. Thus, we can change the second equation to:
Now, we don't know , but we want to, so let's solve for it.
![r = \sqrt[6]{5}](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%5B6%5D%7B5%7D)
Now, the problem is asking us how many rabbits we are going to have after one year (
), so let's find that:
![a = 20 \cdot (\sqrt[6]{5})^{12}](https://tex.z-dn.net/?f=a%20%3D%2020%20%5Ccdot%20%28%5Csqrt%5B6%5D%7B5%7D%29%5E%7B12%7D)
After one year, we will have 500 rabbits.
I’m pretty sure it’s 2x^2 - 12x
A=number of seats in section A
B=number of seats in section B
C=number of seats in section C
We can suggest this system of equations:
A+B+C=55,000
A=B+C ⇒A-B-C=0
28A+16B+12C=1,158,000
We solve this system of equations by Gauss Method.
1 1 1 55,000
1 -1 -1 0
28 16 12 1,158,000
1 1 1 55,000
0 -2 -2 -55,000 (R₂-R₁)
0 12 16 382,000 (28R₁-R₂)
1 1 1 55,000
0 -2 -2 -55,000
0 0 4 52,000 (6R₂+R₃)
Therefore:
4C=52,000
C=52,000/4
C=13,000
-2B-2(13,000)=-55,000
-2B-26,000=-55,000
-2B=-55,000+26,000
-2B=-29,000
B=-29,000 / -2
B=14,500.
A + 14,500+13,000=55,000
A+27,500=55,000
A=55,000-27,500
A=27,500.
Answer: there are 27,500 seats in section A, 14,500 seats in section B and 13,000 seats in section C.
Answer:
x2−3x+3
Step-by-step explanation:
x2+3−3x = x2−3x+3
