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olganol [36]
2 years ago
10

Help me please! I’m begging

Mathematics
1 answer:
leva [86]2 years ago
6 0
Terms: 2, 8, 15. variables: x, y. coefficient:2,8

let me know if it’s correct!
You might be interested in
Q Searchmatics Gr 7)I need 4 cups of flours and 2 cups of sugar to make a cake. How many cups of sugar do I need if Ihave 12 cup
Ede4ka [16]

You will need 6 cups of sugar.

Step - by - Step Explanation

What to find? <em>The number of cups of sugar needed to make a cake with 12 cups of flour.</em>

<em />

Given:

Cups of flours = 4

Cups of sugar = 2

Cups of flour =12

Let x be the number of cups of sugar needed to make a cake with 12 cups of flour.

Using proportion;

4 cups of flour = 2 cups of sugar

12 cups of flour = x

Cross - multiply

4x = 24

Divide both-side of the equation by 4

\frac{\cancel{4}x}{\cancel{4}}=\frac{24}{4}

x =6

Hence, you will need 6 cups of sugar.

6 0
1 year ago
Ally bought 5 different cakes for her birthday. His friends ate 3 1/4 of the amount of cake. Then he gave 1/2 of the cake to his
tamaranim1 [39]

Answer:

7/8 of a cake

Step-by-step explanation:

4 4/4 - 3 1/4 = 1 3/4

7/4 x 1/2 = 7/8

6 0
2 years ago
A piece of cardboard is 13 inches by 26 inches. A square is to be cut from each corner and the sides folded up to make an open-t
Vanyuwa [196]

Answer:

Hence the maximum possible volume will be the 778.53 c.c

Step-by-step explanation:

Given:

A rectangle with 13 x 26 dimensions

And corners are cut to form side squares.

To Find:

Maximum possible volume for box

Solution :

Consider a rectangle of 13 x 26 dimension with and side of square  at corner be x.

(Refer the attachment)

Now,

Formulating the volume equation for the box

So corner square sides we are going to fold up which makes height of the box

and remaining part will be length and breadth

As shown in fig,

Length=26-x

breadth=13-x

And height will be x

V(x)=x*(26-x)*(13-x)

To get maximum volume differentiate the above equation,

V(x)=x*(26*13-26*x-13*x+x^2)

V(x)=x^3-39x^2+338x\\

V'(x)=3x^2-78x+338

V''(x)=6x-78

Now ,Solve the Quadratic Equation to get x values,

3x^2-78x+338=0

x=[-b±(b^2-4ac)^1/2]/2a

x=[78±Sqrt[(78)^2-4*338*3)]/2*3

x=[78±Sqrt(3028)]/6

x=[78±55.027]/6

x=78+55.027/6 or x=78-55.027/6

x=22.17  or x=3.8288

Use these values in 6x-78 to know which value posses the max and min value for the function.

So when x=22.17

6x-78=6*22.17-78

=55.02>0  i.e function will have minimum value .

When x=3.8288

6*3.8288-78

=-55.0272<0 i.e. Function will have maximum value

Now, the function will defines the maximum volume

V(x)=x^3-39x^2+338x

V(x)=3.8288^3-39*(3.82883)^2+338*3.8288

V(x)=56.13-571.73+1294.13

V(x)=778.53 C.C

6 0
3 years ago
Which of the following lines will have a negative slope? Select all that apply
olganol [36]

Answer:

1, 5

Step-by-step explanation:

-16/4=-4

10/5=2

1/2=1/2

-1/-3=1/3

-1/4/1/2=-1/2

The negative ones are your answer.

6 0
1 year ago
Write an equivalent fractions for 7x+4x+3-1
Diano4ka-milaya [45]
11x + 2 is combining like terms
4 0
3 years ago
Read 2 more answers
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