Answer:
- x+y≤80; x≥8; y≥5
- see attached for a graph
- Twenty campers are doing water-based activities and 40 campers are doing ground-based activities.
Step-by-step explanation:
1. Let x and y represent the numbers of campers doing water- and ground-based activities, respectively.
x + y ≤ 80 . . . . . . a maximum of 80 campers can be accommodated
x ≥ 8 . . . . . . . . . . a minimum of 8 campers should be water-based
y ≥ 5 . . . . . . . . . . a minimum of 5 campers should be ground-based
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2. See the attachment for a graph. Possible outcomes are shaded red. The boundary lines of the shaded area are included in the possible outcomes.
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3. Twenty campers are doing water-based activities and 40 campers are doing ground-based activities.
There are no constants here. But we have x and y here.
We will create an equation which is:
2y+3x=54.
But we will also create a second equation which states the number of seats.
x+y=24.
Now we do the two-equation solving method.
2y+3x=54
-2(x+y=24)
2y+3x=54
-2x-2y=-48
x=6
To solve for y, plug in x into one of the original equations. Which one doesn't matter.
y+6=24
y=18
Answer:
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Step-by-step explanation:
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6 times 30 x 6= 180 So the answer is 6
Statements B and C are both true statements.