The equation of the tangent line at x=1 can be written in point-slope form as
... L(x) = f'(1)(x -1) +f(1)
The derivative is ...
... f'(x) = 4x^3 +4x
so the slope of the tangent line is f'(1) = 4+4 = 8.
The value of the function at x=1 is
... f(1) = 1^4 +2·1^2 = 3
So, your linearization is ...
... L(x) = 8(x -1) +3
or
... L(x) = 8x -5
No the sequence common difference changes from 4 to 5 to 6.
So we solve for 1 week and set them equal to each other
first job pay=second job pay
400=175+15%ofsales
x=number of sales
400=175+0.15x
solve for x
subtract 175 from both sides
225=0.15x
divide both sides by 0.15
1500=x
she has to earn $1500 in sales per week to have as much as the other job
Answer:
150 units
Step-by-step explanation:
2(2x)+2(x+12)=4x+2x+(x+3)
4x+2x+24=4x+2x+x+3
24-3=4x+2x+x-4x-2x
21=x
2(21)+(21)+12+2(21)+(21)+12
42+21+12+42+21+12
150
