Find the value of r(q(4)), so first you need to find the value of q(4).
q(4), this means that x = 4, so substitute/plug it into the equation to find the value of q(x) when x = 4:
q(x) = -2x - 1 Plug in 4 into "x" since x = 4
q(4) = -2(4) - 1
q(4) = -8 - 1
q(4) = -9
Now that you know the value of q(4), you can find the value of r(x) when x = q(4)
r(x) = 2x² + 1
r(q(4)) = 2(q(4))² + 1 Plug in -9 into "q(4)" since q(4) = -9
r(q(4)) = 2(-9)² + 1
r(q(4)) = 2(81) + 1
r(q(4)) = 163 163 is the value of r(q(4))
Answer:
degree of polynomial = 5
leading term =
leading coefficient = 2
constant term = -6
Step-by-step explanation:
(i) The degree of the polynomial = 5. That is, the highest power of x
(ii) Leading term = . This is the term with the highest power of x.
(iii) Leading Coefficient = 2. That is, the coefficient of the leading term ()
(iv) Constant term = -6. This is the term that is independent of x or the term in which x doesn't appear.
Answer:
16
Step-by-step explanation:
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Answer:
No, Angela is not correct.
As the method Jim was performing will also lead to the solution.
Step-by-step explanation:
We are given first equation as:
Ax + By = C
Second equation is:
Dx + Ey = F
Jim solved the equation as:
He begins by multiplying equation (1) by D and equation (2) by A.
and so by subtracting both the equations he will obtain a value of y.
and then put the y-value in any of the given two equations to obtain the value of x.
Angela Method:
you should have multiplied equation (1) by E and equation (2) by B.
and when she will subtract both the equations she will get the value of x first and then when she will put the value of x in any of the given equation she will obtain the value of y.
But both will get a value for x and y.
Hence, the method Jim was performing was also correct.